1stopt的擬合問題
在1stopt軟件中,將測得一組數(shù)據(jù)(即不同溫度下藥物的溶解度)利用公式y(tǒng)=a/(a-1+exp(a*b*(1/x-1/398.15)))進行擬合是可以的,但是怎樣對多組測得數(shù)據(jù)在同一個圖中進行線性擬合呢?如圖結(jié)果:
附帶兩組數(shù)據(jù),x y;希望能給出軟件操作的詳細過程,謝謝了
298 0.03937
303 0.00826
308 0.01085
313 0.01718
318 0.0235
323 0.0339
328 0.04308
298 0.00728
303 0.054
308 0.06354
313 0.0778
318 0.09858
323 0.1101
328 0.1353

1.PNG
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Title "多方程擬合";
Parameters a1,b1,a2,b2,a3,d3,a4,b4,a5,b5,a6,b6;
Variables x,y1,y2,y3,y4,y5,y6;
SharedModel;
Function y1=a1/(a1-1+exp(a1*b1*(1/x-1/398.15)));
y2=a2/(a2-1+exp(a2*b2*(1/x-1/398.15)));
y3=a3/(a3-1+exp(a3*b3*(1/x-1/398.15)));
y4=a4/(a4-1+exp(a4*b4*(1/x-1/398.15)));
y5=a5/(a5-1+exp(a5*b5*(1/x-1/398.15)));
y6=a6/(a6-1+exp(a6*b6*(1/x-1/398.15)));
data;
//x y1 y2 y3 y4 y5 y6
298 0.03937 0.00728 ... ... ... ...
303 0.00826 0.05400 ... ... ... ...
308 0.01085 0.06354 ... ... ... ...
313 0.01718 0.07780 ... ... ... ...
318 0.02350 0.09858 ... ... ... ...
323 0.03390 0.11010 ... ... ... ...
328 0.04308 0.13530 ... ... ... ,