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pxjiushun100金蟲(chóng) (小有名氣)
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[交流]
【求助】Wien2K DOS計(jì)算中的問(wèn)題
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我用Wien2K計(jì)算一個(gè)A2B2類(lèi)型的density of states,總的DOS是對(duì)的(積分后等于期待的電子數(shù)),但是每個(gè)原子分別得DOS不對(duì)(即使考慮multiplicity也不行),DOS(A)+DOS(B)不等于totDOS,請(qǐng)問(wèn)這個(gè)是怎么回事,謝謝 [ Last edited by pxjiushun100 on 2010-8-25 at 09:48 ] |
wien2k大雜燴 |
金蟲(chóng) (小有名氣)
金蟲(chóng) (小有名氣)
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Found the answer from Wien2K mailinglist Please note: The total DOS is equal to the sum over the atoms of the total-atomic DOS (inside spheres) and the interstitial-DOS. (Thus in the total-atomic DOS the “multiplicity” of an atom is considered). On the other hand, in the partial (lm-like) DOS the multiplicity is not considered and one obtains the total-atomic DOS as a sum over all partial DOS times the multiplicity. So the total Fe DOS is already multiplied by 2. On the other hand the Fe-s,p,d,eg,... DOS would NOT be multiplied by MULT. Just use "common sense": The total DOS is 6.4; the sum of the DOS inside spheres is 5.6, so obviously 0.8 is the interstitial. You can also check case.outputt, where next to the DOS also the integrated DOS is listed. Compare the integrals at EF with the partial charges in case.scf (:QTL and :CHA0xx ). [ Last edited by pxjiushun100 on 2010-8-26 at 05:30 ] |
銀蟲(chóng) (初入文壇)
金蟲(chóng) (小有名氣)
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