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jingcong198203銅蟲 (初入文壇)
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【討論】小肽含量測(cè)定 已有1人參與
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歐洲藥典6.0版3038頁(yè)測(cè)定Leuprorelinum C59H84N16O12含量的方法用的是高氯酸滴定, 序列5-Oxo-L-prolyl-L-histidyl-L-tryptophyl-L-seryl-L-tyrosyl-D-leucyl-L-leucyl-L-arginyl-N-ethyl-L-prolinamide. 具體內(nèi)容:Dissolve 0.100 g in 3 ml of anhydrous formic acid R. Add 30 ml of anhydrous acetic acid R. Titrate with 0.1 M perchloric acid using 0.1 ml of naphtholbenzein solution R as indicator(萘酚苯基甲醇), until the colour changes from brownish-yellow to green.1 ml of 0.1 M perchloric acid is equivalent to 13.12 mg of C6H13NO2. 還有歐洲藥典上4392頁(yè)的測(cè)定Tetracosactidum也是電位滴定,具體內(nèi)容:Dissolve 0.250 g in 50 ml of alcohol R and add 5.0 ml of 0.01 M hydrochloric acid. Carry out a potentiometric titration (2.2.20), using 0.1 M sodium hydroxide. Read the volume added between the 2 points of inflexion. 1 ml of 0.1 M sodium hydroxide is equivalent to 30.08 mg of C15H25ClN2O2. 我不清楚是什么原理?諸位蟲友,可以給解釋一下嗎,非常感謝! |
銅蟲 (初入文壇)
銅蟲 (初入文壇)
| 不好意思,以下內(nèi)容弄錯(cuò)了。還有歐洲藥典上4392頁(yè)的測(cè)定Tetracosactidum也是電位滴定,具體內(nèi)容:Dissolve 0.250 g in 50 ml of alcohol R and add 5.0 ml of 0.01 M hydrochloric acid. Carry out a potentiometric titration (2.2.20), using 0.1 M sodium hydroxide. Read the volume added between the 2 points of inflexion. 1 ml of 0.1 M sodium hydroxide is equivalent to 30.08 mg of C15H25ClN2O2. |
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