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lov520木蟲(chóng) (小有名氣)
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[交流]
20金幣求高人幫助翻譯
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| 原因可能是催化劑中的金屬氧化物是吸附中心，也是氧化中心，它吸附氧氣聚集在其表面形成氧物種，然后吸附SO3和CO到表面，CO與活潑的氧物種發(fā)生氧化反應(yīng)生成CO2，SO3則形成金屬硫酸鹽。隨著反應(yīng)的進(jìn)行，金屬氧化物逐漸形成金屬硫酸鹽，金屬氧化物的量減少，CO + 1/2O2 → CO2反應(yīng)程度減小，CO2的生成量減�。欢S著CO +1/2O2→CO2和SO2 +1/2O2→SO3反應(yīng)程度的下降，O2含量不斷增加，基本符合實(shí)驗(yàn)數(shù)據(jù)規(guī)律。 |
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benmao_mogu
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3樓2010-06-05 15:33:09
ag_mirabel
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★
lov520(金幣+5, 翻譯EPI+1): 2010-06-05 15:03:36
wypward(金幣+1):歡迎新蟲(chóng)，謝謝參與 2010-06-07 09:33:57
lov520(金幣+5, 翻譯EPI+1): 2010-06-05 15:03:36
wypward(金幣+1):歡迎新蟲(chóng)，謝謝參與 2010-06-07 09:33:57
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The reason might be that the metal oxide of the catalyst is adsorption center as well as oxidation center. It adsorps O2 that accumulates on its surface to form oxygen species. Then, SO3 and CO are adsorped too. CO reacts with the active oxygen species to generate co2, while so3 changes into metal sulfate. With the reaction's undergoing, the metal oxide gradually becomes metal sulfate and decreases. The reduced reaction degree of CO + 1/2O2 → CO2 leads to a decrease in co2's yield quantity. Meanwhile, as the reaction degree of CO +1/2O2→CO2 and SO2 +1/2O2→SO3 lessens, the amount of o2 increases. This agrees with the principles of the experimental data. [ Last edited by ag_mirabel on 2010-6-5 at 11:53 ] |
2樓2010-06-05 11:52:27
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