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blacktea115銀蟲 (小有名氣)
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[交流]
【求助】關(guān)于Cu-O和Cu—N的鍵長問題 已有3人參與
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一般來說Cu-O的鍵長是1.95-2.34 Cu—N的鍵長是1.99。 我的CIF數(shù)據(jù)里的Cu-O和Cu—N數(shù)據(jù)都滿足這些條件,沒有Cu-O,Cu—N=2.6的鍵長。 但在晶體學(xué)報(bào)投稿中,圖PLATON中把鍵長Cu-O,Cu—N=2.6的鍵長也連了起來,二而用SHELXL軟件解是不連的,晶體學(xué)報(bào)E的編輯說是連的,我原來四配位的結(jié)構(gòu)就變成了他所說的extended network,把握拒了,我很頭暈,不知怎么辦,請教達(dá)人。。 |
鐵桿木蟲 (正式寫手)
銀蟲 (小有名氣)
金蟲 (小有名氣)
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The connectivity is determined by d The connectivity is determined by d This is why two different connectivies are represented in different applications. Since "The covalent radii stored in the program are based on experience rather than taken from a specific source" is SHELXTL and "Covalent radii are those given in the Cambridge Structural data base manual" in PLATON. So the latter may be more authoritative even both will be fine. Furthermore, always follow your editor. Good luck! |
金蟲 (小有名氣)
銀蟲 (小有名氣)
銀蟲 (小有名氣)
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