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oytxtu鐵桿木蟲 (正式寫手)
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重金求助 修改幾個邏輯關系緊密的句子
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從方程9，我們可以看到A的大小關系由B(B1/B2)決定。然而，B是與C是密切相關的根據(jù)方程3b。這也就是說明要確定B的話，我們需要先確定C1和C2。因此，我們在圖1里面就給出了不對稱TGNJ的C1和C2之間的關系。由于左電極寬度要小于右電極寬度，所以C1要明顯小于C2。因此，B1要大于B2，i.e., B>1. One can find from Eq. (9) that the magnitude A is determined by the value of B (B=B1/B2). While the B is related to c from Eq. (3b). It indicates that to determine the value of B, one need to determine the C1 and C2 firstly. Hence, in Fig. 1 we present the C1 and C2 for an asymmetric TGNJ. Since the left terminal is narrower than the right terminal, the C1 is quite lower than the C2. Therefor the B1 is larger than B2, i.e., B>1. 這幾個句子，有很多因果關系。出現(xiàn)的therefore, hence這類的詞比較多。 希望蟲友們能幫個忙，使整個小段，更流暢！ 有心的蟲子，可以動動中文，但是意思不能動！ [ Last edited by oytxtu on 2010-8-8 at 09:33 ] |
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xiaoboshen
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oytxtu(金幣+10):謝謝你的幫助！ 2010-08-08 23:08:59
| from Eq. (9)，we can find that the magnitude A is determined by the value of B (B=B1/B2). While the B is closely related to c from Eq. (3b). It indicates that to determine the value of B, the C1 and C2 need to be determined firstly. So we present the relationship between C1 and C2 for an asymmetric TGNJ in Fig. 1. Since the width of the left terminal is narrower than that of the right terminal, the C1 is quite lower than the C2. Therefore， the B1 is larger than B2, i.e., B>1. |
2樓2010-08-08 10:30:44
oytxtu
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oytxtu(金幣+30, 翻譯EPI+1):感謝你的幫助，很地道 2010-08-08 23:08:44
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從方程9中，我們可以看到A的大小關系由B(B1/B2)決定。然而根據(jù)方程3b，B是與C是密切相關的。這也就是說明要確定B的話，我們需要先確定C1和C2。因此，我們在圖1里面就給出了不對稱TGNJ的C1和C2之間的關系。從圖中我們可以清楚的看到C1要明顯小于C2，這是由于左電極寬度要小于右電極寬度。因此，B1要大于B2，i.e., B>1. 我們把B的值代入方程9,我們就最終獲得了A的大小關系。 From Eq. 9 it can be seen that the magnitude of A is determined from B (B=B1/B2). The magnitude of B, however, is calculated from C using Eq. 3b. In the other words, the values of C1 and C2 have to be found first before estimating the value of B. To do so, the relationship between C1 and C2 for an asymmetric TGNJ is given in Fig. 1. It shows that C1 is much smaller than C2 since the left terminal is narrower than the right one. In turn, B1 is larger than B2 with the resultant B value of larger than 1. Finally, by substituting the value of B into Eq. 9, the magnitude of A can be obtained. |
4樓2010-08-08 22:05:27
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