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zbc2008銀蟲 (小有名氣)
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請高手看下審稿人的意見是什么意思.謝謝
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第一次的審稿意見. Do you mean double excitations from the 1s electrons? But if the 1s population changes in the transition (Ka,Kb), the lower state possesses ~-1.0 eV more correlation energy than the upper state. If you have neglected this effect it maybe fairly easy to repair it. It would include calculating the 1s2 pair energy for the few lower states,correcting the wavelengths, and perhaps (except? in the most highly ionized cases) re-scaling the f-values (assuming the length form is proportional to dE). Or do you mean that you exclude double excitations from the valence (n=2) shell? For example,the dynamical correlation 2p2->vd2. These can be energetically important-see for example the paper by Oksuz and Sinanoglu (Phys.Rev.181,54(1969)). If you are excluding either of the two above types,you should provide additional results including these effects to see what energy errors are made by excluding them (say for O I like Krn+). For f-values,exclusion of either of these effects may not be as critical 這是二審的意見 Your text leaves me with the impression that atoms Be through Ne include just single excitation. One interpretation of that is you do a Dirac-Fock single configuration calculation (I suppose that is N=0 for you) and add single excitations to that. For example for He-like Kr, this would include 1s2 + 1s. Is that what you are doing? If so, it's unacceptable when you're breaking the K shell. There is ~1.0 eV in that shell which contributes directly to the energy differences of interest to you. For example (He-like) 1s2 -> vp2 supplies about 0.5 eV of the 1.0 eV. Is that present for you for B-like to Ne-like krypton? If we agree on what you actually did, then you need to replace "single excitation" with something more accurate (would this be an n=1 level calculation?) 希望某位高手解釋下這個(gè)意見是什么意思.有沒有好的方法解決.謝謝你在百忙中看這條消息 |
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