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| 在添加新規(guī)則15時(shí),通過查找B0的范圍搜索樹將返回點(diǎn)b70,又發(fā)現(xiàn)規(guī)則b70 規(guī)則索引表的第1項(xiàng)是規(guī)則10,新規(guī)則15與規(guī)則10并非是獨(dú)立的,所以不能添加進(jìn)B1;規(guī)則索引表的第1項(xiàng)是-1,規(guī)則15將與B2中的前一條非-1規(guī)則即規(guī)則7比較,它們也不是獨(dú)立的, 所以不能添加進(jìn)B2;規(guī)則索引表的第3項(xiàng)是-1,規(guī)則15將與B3中的前一條非-1規(guī)則即規(guī)則14比較,它們是獨(dú)立的,所以規(guī)則15最終將添加到獨(dú)立集合B3中。規(guī)則15的起點(diǎn)bnew是B0中沒有的新端點(diǎn),需要將bnew添加到B0中,并且為其創(chuàng)建規(guī)則索引表(-1,7,15),同時(shí)更新b70的索引表為(10,-1,15)。 |
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when we add a new Rule 15, the search tree will return to the point of B70 through researching the range of B0. Then we find the Role b70 and the item 1 of the index table is Rule 10. The new Rule 15 and Rule 10 are not independent, so we could not add Rule B1; item 1 of the table index is -1. Rule 15 and Rule 7, which is the former rule of B2 and is non-1, are not independent either, so we could not either added B2 here; item 3 of the index table is -1, Rule 15 and Rule 14, which is the former rule of B3 and is -1, are independent, so Rule 15 will eventually be added to the independent set B3. The starting point of Rule 15 is bnew, which is a new endpoint and does not appear in B0. we have to add bnew into Bo, to create a rule index table (-1,7,15), and also to update the index table b70 (10, -1, 15). 實(shí)在是有些地方看不明白你想表達(dá)什么。根據(jù)我自己的理解譯成這樣 |
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