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qiqi2926銅蟲 (小有名氣)
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[交流]
【求助】新手學(xué)習(xí)siesta,出現(xiàn)錯(cuò)誤,現(xiàn)求助 已有2人參與
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背景:(新手,有些關(guān)鍵詞的意思不理解) 作cutoff的收斂測試。 腳本如下: libh4.fdf : SystemName libh4 SystemLabel libh4 NumberOfAtoms 24 NumberOfSpecies 3 %block ChemicalSpeciesLabel 1 1 H 2 3 Li 3 5 B %endblock ChemicalSpeciesLabel LatticeConstant 6.4494 5.3070 5.2919 Ang %block LatticeVectors 1.000000000000000 0.000000000000000 0.000000000000000 0.000000000000000 1.000000000000000 0.000000000000000 0.000000000000000 0.000000000000000 1.000000000000000 %endblock LatticeVectors AtomicCoordinatesFormat ScaledCartesian #ScaledByLatticeVectors %block AtomicCoordinatesAndAtomicSpecies 0.0949999988079071 0.3339999914169312 0.0740000009536743 1 h 0.0949999988079071 0.8339999914169313 0.5740000009536742 1 h -0.0949999988079071 -0.3339999914169312 0.0740000009536743 1 h -0.0949999988079071 0.1660000085830689 0.5740000009536743 1 h 0.5949999988079071 -0.3339999914169312 0.0740000009536743 1 h 0.5949999988079071 0.1660000085830688 0.5740000009536743 1 h 0.4050000011920930 0.3339999914169312 0.0740000009536743 1 h 0.4050000011920930 0.8339999914169310 0.5740000009536743 1 h 0.2500000000000000 0.0496999993920326 0.1831000000238419 1 h 0.2500000000000000 0.3510000109672546 0.3802999854087830 1 h 0.2500000000000000 0.5496999993920326 0.6831000000238418 1 h 0.2500000000000000 0.8510000109672545 0.8802999854087830 1 h -0.2500000000000000 -0.0496999993920326 0.1831000000238419 1 h -0.2500000000000000 -0.3510000109672546 0.3802999854087830 1 h -0.2500000000000000 0.4503000006079674 0.6831000000238419 1 h -0.2500000000000000 0.1489999890327454 0.8802999854087829 1 h 0.0000000000000000 0.0000000000000000 0.0000000000000000 2 li 0.0000000000000000 0.5000000000000000 0.4999999999999999 2 li 0.5000000000000000 -0.0000000000000000 -0.0000000000000000 2 li 0.5000000000000000 0.4999999999999999 0.5000000000000000 2 li 0.2500000000000000 0.2712000012397766 0.1729999929666519 3 b 0.2500000000000000 0.7712000012397767 0.6729999929666518 3 b -0.2500000000000000 -0.2712000012397766 0.1729999929666519 3 b -0.2500000000000000 0.2287999987602234 0.6729999929666519 3 b %endblock AtomicCoordinatesAndAtomicSpecies MeshCutoff 40.0 Ry #%block kgrid-monkhorst-pack # 9 0 0 0.0 # 0 9 0 0.0 # 0 0 9 0.0 #%endblock kgrid-monkhorst-pack 出現(xiàn)的錯(cuò)誤為: 。。。。。。 WARNING: Minimum split_norm parameter: 0.15550. Will not be able to generate orbital with split_norm = 0.15000 See manual for new split options ERROR STOP from Node: 0 |
木蟲 (著名寫手)

銅蟲 (小有名氣)
木蟲 (著名寫手)

銅蟲 (小有名氣)
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我將這個(gè)參數(shù)分別改成0.20和0.25,運(yùn)行出來的結(jié)果也有差異,所以說這個(gè)參數(shù)并不是無關(guān)緊要的。而這兩個(gè)參數(shù)的選取應(yīng)該有一個(gè)優(yōu)先順序的,這個(gè)順序應(yīng)該根據(jù)什么量來選擇呢,總能,原子間的力,還是其他??? 還有就是siesta計(jì)算相同體系,得到的總能遠(yuǎn)大于VASP以及abinit計(jì)算出總能的值,這個(gè)還是需要您來說明一下。 最后就是:能不能推薦一些教程或者手冊之類的??user guide給的內(nèi)容還是有點(diǎn)亂,可能是我還沒有適應(yīng)siesta的文件吧。。。 |
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