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我家小屁孩銅蟲 (小有名氣)
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[求助]
量化中出錯(cuò)的log文件
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蟲蟲們好: 有勞見多識(shí)廣的蟲蟲幫俺分析一下此log文件出錯(cuò)的原因并怎樣改正,單線態(tài)已順利完成,在算五線態(tài)時(shí)出錯(cuò)了,多謝了。。! Gaussian 09: EM64L-G09RevA.01 8-May-2009 17-Aug-2011 ****************************************** %chk=/home/lyy/dqs/perpen.chk %mem=2000MB %nprocshared=4 Will use up to 4 processors via shared memory. --------------------------------------------------- # opt freq=noraman b3lyp/6-31g(d) geom=connectivity --------------------------------------------------- 1/14=-1,18=20,19=15,26=3,38=1,57=2/1,3; 2/9=110,12=2,17=6,18=5,40=1/2; 3/5=1,6=6,7=1,11=2,16=1,25=1,30=1,71=1,74=-5/1,2,3; 4//1; 5/5=2,38=5/2; 6/7=2,8=2,9=2,10=2,28=1/1; 7//1,2,3,16; 1/14=-1,18=20,19=15/3(2); 2/9=110/2; 99//99; 2/9=110/2; 3/5=1,6=6,7=1,11=2,16=1,25=1,30=1,71=1,74=-5/1,2,3; 4/5=5,16=3/1; 5/5=2,38=5/2; 7//1,2,3,16; 1/14=-1,18=20,19=15/3(-5); 2/9=110/2; 6/7=2,8=2,9=2,10=2,19=2,28=1/1; 99/9=1/99; ------ perpen ------ Symbolic Z-matrix: Charge = 0 Multiplicity = 5 (中間部分略) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) (A) The electronic state of the initial guess is 5-A. Initial guess Requested convergence on RMS density matrix=1.00D-08 within 128 cycles. Requested convergence on MAX density matrix=1.00D-06. Requested convergence on energy=1.00D-06. No special actions if energy rises. EnCoef did 100 forward-backward iterations EnCoef did 11 forward-backward iterations EnCoef did 3 forward-backward iterations EnCoef did 6 forward-backward iterations EnCoef did 5 forward-backward iterations EnCoef did 3 forward-backward iterations Rare condition: small coef for last iteration: 0.000D+00 Rare condition: small coef for last iteration: 0.000D+00 Restarting incremental Fock formation. Rare condition: small coef for last iteration: 0.000D+00 Restarting incremental Fock formation. Restarting incremental Fock formation. Restarting incremental Fock formation. Restarting incremental Fock formation. Restarting incremental Fock formation. >>>>>>>>>> Convergence criterion not met. SCF Done: E(UB3LYP) = -4473.53934912 A.U. after 129 cycles Convg = 0.2980D-04 -V/T = 2.0026 Annihilation of the first spin contaminant: S**2 before annihilation 6.0847, after 6.0019 DiagDN has N= 676 LTot= 2060 but NE2= 3 cannot use DSYEVD. Convergence failure -- run terminated. Error termination via Lnk1e in /home/lyy/g09/l502.exe at Thu Aug 18 02:36:02 2011. Job cpu time: 0 days 18 hours 8 minutes 33.1 seconds. File lengths (MBytes): RWF= 427 Int= 0 D2E= 0 Chk= 11 Scr= 1 小女是實(shí)驗(yàn)為主,量化知識(shí)淺薄,希望能得到高手蟲蟲們的指點(diǎn)! |
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鐵桿木蟲 (著名寫手)
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無(wú)他,構(gòu)型不好而已... 1. 改構(gòu)型 2. 可用 scfcyc=500 增大scf計(jì)算的cycle,默認(rèn)的是129 (SCF Done: E(UB3LYP) = -4473.53934912 A.U. after 129 cycles) 3. scf=qc,用了這個(gè),速度很慢;所以一般用scf=qc算第一點(diǎn)即可,然后再讀取第一點(diǎn)的chk文件繼續(xù)往下做... |
金蟲 (著名寫手)
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如果還不行,只能拿出殺手锏了,就是使用qc,但不建議直接使用,而是使用xqc關(guān)鍵詞,比如scf=(maxcycle=80,xqc),意思是如果scf正常計(jì)算(dc)在80個(gè)循環(huán)之內(nèi)不收斂才進(jìn)行昂貴的qc計(jì)算,因?yàn)閟cf不收斂多數(shù)在幾個(gè)優(yōu)化的過(guò)程中出現(xiàn),無(wú)法判斷哪一步優(yōu)化的時(shí)候會(huì)出現(xiàn)scf不收斂,所以用xqc比純粹使用qc要省時(shí)的多。 使用scf=qc,這個(gè)計(jì)算會(huì)慢,而且需要用stable關(guān)鍵字來(lái)測(cè)試結(jié)果是否波函數(shù)穩(wěn)定。如果這個(gè)還不收斂,會(huì)提示L508錯(cuò)誤,請(qǐng)問如何測(cè)試波函數(shù)穩(wěn)定啊,是加上關(guān)鍵詞scf=xqc stable 就可以么,即# opt freq rb3lyp/6-31+g(d) pop=(nbo,savenbo,full) scf=xqc stable 謝謝啊 |

鐵桿木蟲 (著名寫手)
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測(cè)試波函數(shù)穩(wěn)定否,用stable=opt,只需算一個(gè)單點(diǎn)即可,不用算freq之類 例如 # hf/6-31g* stable=opt 若用scf=qc,也可以寫成 # hf/6-31g* stable=opt scf=qc 如要在波函數(shù)穩(wěn)定的基礎(chǔ)上繼續(xù)優(yōu)化或算freq,可用--link1-- # hf/6-31g* stable=opt scf=qc ... ... ... 空一行 --link1-- %chk=...跟上面的一致... # hf/6-31g* opt freq=noraman guess=read geom=allcheck |
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