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[求助]
請教一下15%的HF交換是哪種方法,求相關(guān)資料
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| 審稿人提到用 the use of 15% HF exchange in B3LYP. 是什么方法?求助大師解決,是M05-2X?還是別的呢?謝謝啦。。。 |
鐵桿木蟲 (職業(yè)作家)
站在計(jì)算化學(xué)入門的門檻上
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#P BLYP IOp(3/76=1000001500) IOp(3/77=0720008000) IOp(3/78=0810010000) 這樣就是15%HF的B3LYP http://www.gaussian.com/g_tech/g_ur/k_dft.htm |

禁蟲 (文壇精英)
密度泛函·小卒
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你這個(gè)錯(cuò)誤跟人家lihb網(wǎng)友教你的東西毫無關(guān)系 lanl2tz基組不是高斯自定義的基組 你用lanl2tz做Zn 應(yīng)該如下輸入 Zn 0 S 1 1.00 0.7997000 1.0000000 S 1 1.00 0.1752000 1.0000000 S 1 1.00 0.0556000 1.0000000 P 1 1.00 0.1202000 1.0000000 P 1 1.00 0.0351000 1.0000000 D 3 1.00 68.8500000 0.0258532 18.3200000 0.1651195 5.9220000 0.4468212 D 1 1.00 1.9270000 1.0000000 D 1 1.00 0.5528000 1.0000000 **** Zn 0 ZN-ECP 3 18 f potential 5 1 386.7379660 -18.0000000 2 72.8587359 -124.3527403 2 15.9066170 -30.6601822 2 4.3502340 -10.6358989 2 1.2842199 -0.7683623 s-f potential 5 0 19.0867858 3.0000000 1 5.0231080 22.5234225 2 1.2701744 48.4465942 2 1.0671287 -44.5560119 2 0.9264190 12.9983958 p-f potential 5 0 43.4927750 5.0000000 1 20.8692669 20.7435589 2 21.7118378 90.3027158 2 6.3616915 74.6610316 2 1.2291195 9.8894424 d-f potential 3 2 13.5851800 -4.8490359 2 9.8373050 3.6913379 2 0.8373113 -0.5037319 |
鐵桿木蟲 (職業(yè)作家)
站在計(jì)算化學(xué)入門的門檻上

鐵桿木蟲 (職業(yè)作家)
站在計(jì)算化學(xué)入門的門檻上

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我按你說的lanl2tz做的Zn原子 出現(xiàn)以下錯(cuò)誤: Leave Link 202 at Thu Feb 23 21:18:59 2012, MaxMem= 117964800 cpu: 0.1 (Enter /home/lcq/g03/l301.exe) General basis read from cards: (5D, 7F) Centers: 6 10 12 13 19 23 24 26 1 4 5 7 18 20 9 11 22 25 8 14 Centers: 15 16 17 21 27 28 29 30 cc-PVTZ **** Centers: 2 3 Lanl2tz QPERR --- A SYNTAX ERROR WAS DETECTED IN THE INPUT LINE. Lanl2tz ' Last state="Top" TCursr= 746 LCursr= 0 Error reading general basis specification. Error termination via Lnk1e in /home/lcq/g03/l301.exe at Thu Feb 23 21:18:59 2012. Job cpu time: 0 days 0 hours 0 minutes 2.4 seconds. File lengths (MBytes): RWF= 13 Int= 0 D2E= 0 Chk= 1 Scr= 1 是怎么回事?是不是不適合鋅呢 |
禁蟲 (文壇精英)
密度泛函·小卒
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