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[求助]
如何從輸出文件中讀取第一激發(fā)能
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請(qǐng)教各位高手 N2 的第一激發(fā)能在log文件中怎么讀取呢。我的輸入文件中是: #p td(nstates=5,singlets,root=1) iop(5/13=1) b3lyp/6-31+g* 輸出文件 Excited State 1: Singlet-?Sym 9.1556 eV 135.42 nm f=0.0000 7 -> 8 0.67423 This state for optimization and/or second-order correction. Total Energy, E(RPA) = -109.193316651 Copying the excited state density for this state as the 1-particle RhoCI density. Excited state symmetry could not be determined. Excited State 2: Singlet-?Sym 9.1556 eV 135.42 nm f=0.0000 7 -> 9 0.67423 Excited state symmetry could not be determined. Excited State 3: Singlet-?Sym 9.1918 eV 134.89 nm f=0.0000 5 -> 9 -0.48284 6 -> 8 0.48284 Excited state symmetry could not be determined. Excited State 4: Singlet-?Sym 9.6066 eV 129.06 nm f=0.0000 5 -> 8 0.50305 6 -> 9 -0.50305 Excited state symmetry could not be determined. Excited State 5: Singlet-?Sym 9.6066 eV 129.06 nm f=0.0000 5 -> 9 0.50305 6 -> 8 0.50305 有人告訴我第一激發(fā)能是9.1556。但是文獻(xiàn)報(bào)道的是6.942.差的特別懸殊。 請(qǐng)問(wèn)直接讀的那個(gè)是正確的嗎,我的計(jì)算方法基組都是完全重復(fù)文獻(xiàn)中的。第一激發(fā)能到底怎么算呢,請(qǐng)高手指點(diǎn)迷津,不勝感激 |
鐵桿木蟲(chóng) (正式寫(xiě)手)
金蟲(chóng) (著名寫(xiě)手)
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