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[求助]
關(guān)于動(dòng)力學(xué)的 求助各位大神 傾全部財(cái)產(chǎn)求解啊
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| 假如我做了5個(gè)不同濃度的降解實(shí)驗(yàn),他們都能用一級(jí)動(dòng)力學(xué)曲線擬合,那么擬合出來的k值會(huì)是一樣的嗎?還是會(huì)不同(我擬合的是這種情況,用其他的擬合相關(guān)性不太好)。如果不同,那么計(jì)算出的半衰期也就不同了,這樣的話跟一級(jí)動(dòng)力學(xué)的定義半衰期不隨初始濃度改變不就矛盾了嗎?求大家?guī)椭?! 寫文章要急用 |
木蟲 (著名寫手)
鐵蟲 (初入文壇)

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Concentration (mg/L) Degradation rate (%) Kinetic equation Reaction order R2 Half-life time t1/2(h) 300 99.21% C= 314.4e-0.0235t first-order 0.989 29.5 450 95.99% C= 476.6e-0.0147t first-order 0.967 47.2 600 91.84% C= 611.6e-0.0133t first-order 0.992 52.1 750 83.47% C= 314.4e-0.00549t first-order 0.995 126.3 謝謝您的答復(fù),可是您看這個(gè)t1/2差距是不是差距太大了 |
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Concentration (mg/L) Degradation rate (%) Kinetic equation Reaction order R2 Half-life time t1/2(h) 300 99.21% C= 314.4e-0.0235t first-order 0.989 29.5 450 95.99% C= 476.6e-0.0147t first-order 0.967 47.2 600 91.84% C= 611.6e-0.0133t first-order 0.992 52.1 750 83.47% C= 314.4e-0.00549t first-order 0.995 126.3 謝謝您的答復(fù),可是您看這個(gè)t1/2差距是不是差距太大了 |
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Concentration (mg/L) Degradation rate (%) Kinetic equation Reaction order R2 Half-life time t1/2(h) 300 99.21% C= 314.4e-0.0235t first-order 0.989 29.5 450 95.99% C= 476.6e-0.0147t first-order 0.967 47.2 600 91.84% C= 611.6e-0.0133t first-order 0.992 52.1 750 83.47% C= 314.4e-0.00549t first-order 0.995 126.3 謝謝您的答復(fù),可是您看這個(gè)t1/2的變化不能叫做誤差了吧 |
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Concentration (mg/L) Degradation rate (%) Kinetic equation Reaction order R2 Half-life time t1/2(h) 300 99.21% C= 314.4e-0.0235t first-order 0.989 29.5 450 95.99% C= 476.6e-0.0147t first-order 0.967 47.2 600 91.84% C= 611.6e-0.0133t first-order 0.992 52.1 750 83.47% C= 314.4e-0.00549t first-order 0.995 126.3 謝謝您的答復(fù),可是您看這個(gè)t1/2差距是不是差距太大了 |
木蟲 (著名寫手)
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