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qs001新蟲(chóng) (初入文壇)
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[求助]
fsolve計(jì)算結(jié)果問(wèn)題
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計(jì)算結(jié)果感覺(jué)誤差好大,是由于初值取值造成的影響嗎,還是要設(shè)置option來(lái)控制精度,第一次使用matlab一竅不通,請(qǐng)大家?guī)兔聪隆?br />
First-Order Norm of Iteration Func-count Residual optimality Lambda step 0 8 39.2026 1.13e+003 0.01 1 16 0.00103045 0.705 0.001 0.294456 2 24 3.55079e-005 0.0727 0.0001 0.237055 3 32 7.28141e-006 0.19 1e-005 0.144512 4 40 2.91808e-006 0.0123 1e-006 0.0248491 5 48 2.90763e-006 3.58e-007 1e-007 0.000338087 6 56 2.90763e-006 1.02e-009 1e-008 1.90914e-006 Equation solved, fsolve stalled. fsolve stopped because the relative size of the current step is less than the default value of the step size tolerance and the vector of function values is near zero as measured by the selected value of the function tolerance. y = -2.2413 2.2083 -0.1310 0.1318 1.0596 0.0211 -0.0272 fval = 0.0000 0.0008 -0.0008 0.0003 0.0000 0.0000 -0.0011 0.0006 下面是我要解的方程組 function F=myfun(x) b=1;a=1; F=[-0.0575*x(3)/a-x(7)*a*0.5-x(6); x(3)/a^2+x(4)+17.39*x(7)*log(a)+0.8695652174*b*log(a); -x(1)/(x(5)^2)-x(2)+x(3)/(x(5)^2)+x(4)-92.49880554*x(7)*log(x(5))+0.8695652174*b*log(x(5)); 0.0065*x(1)/x(5)-0.0026*x(2)*x(5)-0.0575*x(3)/x(5)+x(7)*x(5)*((0.7-0.4*log(x(5)))/1.4-0.9347826087); -2*x(1)/(x(5)^2)+109.8901099*x(7)-b; 2*x(1)/(1.5^2)-109.8901099*x(7)-b; 0.444444444444444*x(1)/a^2+x(2)+109.8901099*x(7)*log(1.5*a); -x(1)*log(1.5*a/x(5))+0.5*(1.5^2*a^2-x(5)^2)*x(2)-x(3)*log(x(5)/a)+0.5*(x(5)^2-a^2)*x(4)+17.39130435*x(7)*(0.5*x(5)^2*(log(x(5))+0.5)-0.5*a^2*(log(a)+0.5))+109.8901099*x(7)*(0.5*1.5*1.5*a^2*(0.5+log(1.5*a))-0.5*x(5)^2*(log(x(5))+0.5))+0.0209742*1.5^2*a^2*b+0.8695652174*b*(0.5*x(5)^2*(log(x(5))+0.5)-0.5*a^2*(log(a)+0.5))]; 選取的初值是x0=[-2,2,-0.5,0.5,1.05,0.01,-0.01] |
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