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[求助]
求解決在gaussian中用TS求過渡態(tài)的 L103問題 已有1人參與
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輸入的文本。。。。。。 %chk=ch2o-1.chk # opt=(calcfc,ts,cartesian) freq=noraman b3lyp/6-31g(d) Title Card Required 0 1 C 0.00000000 0.00000000 0.00000000 O -0.39825858 0.00001922 1.16090358 H 0.80799608 0.00000000 -0.76174661 H -1.09713225 0.00005296 0.17151207 本人用此文本進(jìn)行找過渡態(tài),,可是結(jié)果提示L103錯(cuò)誤,,不解(新手) 還請(qǐng)各位大蝦幫個(gè)忙,,,,, 得出的結(jié)果雖然有頻率,但是這些結(jié)果和用QST2找的不一樣。。。。。。。。。 and normal coordinates: 1 2 3 A A A Frequencies -- -2091.0713 760.6086 1330.8638 Red. masses -- 1.1103 1.1310 1.7830 Frc consts -- 2.8604 0.3855 1.8606 IR Inten -- 719.5755 91.3427 91.8460 Atom AN X Y Z X Y Z X Y Z 1 6 -0.08 -0.02 0.00 0.00 0.00 0.11 -0.16 -0.05 0.00 2 8 -0.01 0.05 0.00 0.00 0.00 0.01 0.18 0.02 0.00 3 1 0.10 -0.15 0.00 0.00 0.00 -0.70 -0.84 0.47 0.00 4 1 0.90 -0.38 0.00 0.00 0.00 -0.70 -0.05 -0.12 0.00 4 5 6 A A A Frequencies -- 1460.2954 2618.0058 2875.6157 Red. masses -- 2.6211 1.0287 1.1149 Frc consts -- 3.2932 4.1540 5.4320 IR Inten -- 72.4295 238.0354 47.9643 Atom AN X Y Z X Y Z X Y Z 1 6 0.26 -0.17 0.00 0.02 0.00 0.00 0.06 0.08 0.00 2 8 -0.17 0.10 0.00 -0.01 0.03 0.00 0.00 0.01 0.00 3 1 -0.74 0.48 0.00 0.25 0.35 0.00 -0.53 -0.74 0.00 4 1 0.30 0.03 0.00 -0.33 -0.84 0.00 -0.15 -0.38 0.00 ------------------- - Thermochemistry - ------------------- Temperature 298.150 Kelvin. Pressure 1.00000 Atm. Atom 1 has atomic number 6 and mass 12.00000 Atom 2 has atomic number 8 and mass 15.99491 Atom 3 has atomic number 1 and mass 1.00783 Atom 4 has atomic number 1 and mass 1.00783 Molecular mass: 30.01056 amu. Principal axes and moments of inertia in atomic units: 1 2 3 Eigenvalues -- 7.04560 47.34034 54.38593 X 0.99370 0.11204 0.00000 Y -0.11204 0.99370 0.00000 Z 0.00000 0.00000 1.00000 This molecule is an asymmetric top. Rotational symmetry number 1. Rotational temperatures (Kelvin) 12.29333 1.82960 1.59258 Rotational constants (GHZ): 256.15170 38.12270 33.18397 1 imaginary frequencies ignored. Zero-point vibrational energy 54103.4 (Joules/Mol) 12.93103 (Kcal/Mol) Vibrational temperatures: 1094.34 1914.81 2101.04 3766.72 4137.36 (Kelvin) Zero-point correction= 0.020607 (Hartree/Particle) Thermal correction to Energy= 0.023546 Thermal correction to Enthalpy= 0.024490 Thermal correction to Gibbs Free Energy= -0.001146 Sum of electronic and zero-point Energies= -114.334802 Sum of electronic and thermal Energies= -114.331863 Sum of electronic and thermal Enthalpies= -114.330919 Sum of electronic and thermal Free Energies= -114.356555 E (Thermal) CV S KCal/Mol Cal/Mol-Kelvin Cal/Mol-Kelvin Total 14.775 6.900 53.956 Electronic 0.000 0.000 0.000 Translational 0.889 2.981 36.130 Rotational 0.889 2.981 17.546 Vibrational 12.998 0.939 0.280 Q Log10(Q) Ln(Q) Total Bot 0.336758D+01 0.527318 1.214194 Total V=0 0.101349D+11 10.005819 23.039250 Vib (Bot) 0.341812D-09 -9.466213 -21.796761 Vib (V=0) 0.102870D+01 0.012289 0.028296 Electronic 0.100000D+01 0.000000 0.000000 Translational 0.646199D+07 6.810366 15.681448 Rotational 0.152463D+04 3.183164 7.329506 ***** Axes restored to original set ***** ------------------------------------------------------------------- Center Atomic Forces (Hartrees/Bohr) Number Number X Y Z ------------------------------------------------------------------- 1 6 0.000368794 -0.000000026 -0.000131324 2 8 -0.000002796 -0.000000002 0.000098347 3 1 -0.000195254 0.000000014 0.000007039 4 1 -0.000170743 0.000000014 0.000025938 ------------------------------------------------------------------- Cartesian Forces: Max 0.000368794 RMS 0.000138725 GradGradGradGradGradGradGradGradGradGradGradGradGradGradGradGradGradGrad Berny optimization. NTrRot= -1 NTRed= 6 NAtoms= 4 NSkip= 0 IsLin=F Error in internal coordinate system. Error termination via Lnk1e in /export/g09/l103.exe at Thu Jan 3 01:27:27 2002. Job cpu time: 0 days 0 hours 0 minutes 35.8 seconds. File lengths (MBytes): RWF= 5 Int= 0 D2E= 0 Chk= 1 Scr= |
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