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future_wl木蟲 (著名寫手)
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[求助]
La摻雜BiFeO3時反鐵磁性的設(shè)置問題
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我用R3c菱方表示的模型基礎(chǔ)上建了2*2*2的超胞,然后用La取代了一個Bi,分子式變成了Bi15LaFe16O48 POSCAR 如下: BiLaFeO3 1.0 11.2735004425 0.0000000000 0.0000000000 5.7346471374 9.7059587077 0.0000000000 5.7346471374 3.2725638144 9.1376124079 O Bi Fe La 48 15 16 1 Direct 0.198650002 0.261649996 0.471150011 0.471150011 0.198650002 0.261649996 0.261649996 0.471150011 0.198650002 0.011650000 0.448650002 0.221149996 0.448650002 0.221149996 0.011650000 0.221149996 0.011650000 0.448650002 0.698650002 0.261649996 0.471150011 0.971149981 0.198650002 0.261649996 0.761650026 0.471150011 0.198650002 0.511650026 0.448650002 0.221149996 0.948650002 0.221149996 0.011650000 0.721149981 0.011650000 0.448650002 0.198650002 0.761650026 0.471150011 0.471150011 0.698650002 0.261649996 0.261649996 0.971149981 0.198650002 0.011650000 0.948650002 0.221149996 0.448650002 0.721149981 0.011650000 0.221149996 0.511650026 0.448650002 0.698650002 0.761650026 0.471150011 0.971149981 0.698650002 0.261649996 0.761650026 0.971149981 0.198650002 0.511650026 0.948650002 0.221149996 0.948650002 0.721149981 0.011650000 0.721149981 0.511650026 0.448650002 0.198650002 0.261649996 0.971149981 0.471150011 0.198650002 0.761650026 0.261649996 0.471150011 0.698650002 0.011650000 0.448650002 0.721149981 0.448650002 0.221149996 0.511650026 0.221149996 0.011650000 0.948650002 0.698650002 0.261649996 0.971149981 0.971149981 0.198650002 0.761650026 0.761650026 0.471150011 0.698650002 0.511650026 0.448650002 0.721149981 0.948650002 0.221149996 0.511650026 0.721149981 0.011650000 0.948650002 0.198650002 0.761650026 0.971149981 0.471150011 0.698650002 0.761650026 0.261649996 0.971149981 0.698650002 0.011650000 0.948650002 0.721149981 0.448650002 0.721149981 0.511650026 0.221149996 0.511650026 0.948650002 0.698650002 0.761650026 0.971149981 0.971149981 0.698650002 0.761650026 0.761650026 0.971149981 0.698650002 0.511650026 0.948650002 0.721149981 0.948650002 0.721149981 0.511650026 0.721149981 0.511650026 0.948650002 0.000000000 0.000000000 0.000000000 0.250000000 0.250000000 0.250000000 0.500000000 0.000000000 0.000000000 0.750000000 0.250000000 0.250000000 0.000000000 0.500000000 0.000000000 0.500000000 0.500000000 0.000000000 0.750000000 0.750000000 0.250000000 0.000000000 0.000000000 0.500000000 0.250000000 0.250000000 0.750000000 0.500000000 0.000000000 0.500000000 0.750000000 0.250000000 0.750000000 0.000000000 0.500000000 0.500000000 0.250000000 0.750000000 0.750000000 0.500000000 0.500000000 0.500000000 0.750000000 0.750000000 0.750000000 0.110600002 0.110600002 0.110600002 0.360599995 0.360599995 0.360599995 0.610599995 0.110600002 0.110600002 0.860599995 0.360599995 0.360599995 0.110600002 0.610599995 0.110600002 0.360599995 0.860599995 0.360599995 0.610599995 0.610599995 0.110600002 0.860599995 0.860599995 0.360599995 0.110600002 0.110600002 0.610599995 0.360599995 0.360599995 0.860599995 0.610599995 0.110600002 0.610599995 0.860599995 0.360599995 0.860599995 0.110600002 0.610599995 0.610599995 0.360599995 0.860599995 0.860599995 0.610599995 0.610599995 0.610599995 0.860599995 0.860599995 0.860599995 0.250000000 0.750000000 0.250000000 請問大家: 1. 在進行計算的時候,這個體系還需要和BiFeO3本征體系一樣設(shè)置為反鐵磁的嗎? 2. 如果設(shè)置反鐵磁,我在INCAR 中設(shè)置 MAGMOM= 48*0 15*0 8*-6 8*6 0是否可以,需不需要在POSCAR 中將原子數(shù)寫為如下形式: O Bi Fe Fe La 48 15 8 8 1 3. POTCAR中Fe的贗勢文件,用一個還是兩個 期待大家的幫助,謝謝。! 附上結(jié)構(gòu)優(yōu)化的INCAR : SYSTEM=BiLaFeO3 ENCUT=800 ISMEAR=0 IBRION=2 ISIF=3 NSW=400 EDIFF=1E-6 EDIFFG=1E-5 EDIFFG=-0.01 ISTART=0 ICHARG=2 ISPIN=2 PREC=A SIGMA=0.1 MAGMOM= 48*0 15*0 8*-6 8*6 0 LREAL=AUTO LWAVE=.FALSE LCHARG=.FALSE |
第一性原理 |

木蟲 (著名寫手)

木蟲 (著名寫手)

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