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climbnail銅蟲 (小有名氣)
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[求助]
0.1 N高氯酸 與 0.1 N高氯酸in醋酸 一樣嗎？
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請問各位高手 USP36里面有用 0.1 N perchloric acid VS滴定的實驗 這里的0.1 N perchloric acid VS是怎么配的？ 這個0.1 N perchloric acid VS和下面這個是一個東西嗎？ Perchloric acid ( 0.1 N高氯酸在醋酸標準液 ) in anhydrous acetic acid, for titrations in non-aqueous media c(HClO4) = 0.1 mol/l (0.1 N) TitriPUR® |
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yugijiang
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4樓2013-06-05 16:43:46
yugijiang
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【答案】應助回帖
★ ★ ★ ★ ★
感謝參與，應助指數(shù) +1
climbnail: 金幣+5, 謝謝！但等進一步告訴我這個資料的出處嗎？ 2013-06-05 15:21:54
感謝參與，應助指數(shù) +1
climbnail: 金幣+5, 謝謝！但等進一步告訴我這個資料的出處嗎？ 2013-06-05 15:21:54
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Perchloric Acid, Tenth-Normal (0.1 N) in Glacial Acetic Acid HClO4, 100.46 10.05 g in 1000 mL [NOTE—Where called for in the tests and assays, this volumetric solution is specified as “0.1 N perchloric acid.” Thus, where 0.1 N or other strength of this volumetric solution is specified, the solution in glacial acetic acid is to be used, unless the words “in dioxane” are stated. [See also Perchloric Acid, Tenth-Normal (0.1 N) in Dioxane.] ] Mix 8.5 mL of perchloric acid with 500 mL of glacial acetic acid and 21 mL of acetic anhydride, cool, and add glacial acetic acid to make 1000 mL. Alternatively, the solution may be prepared as follows. Mix 11 mL of 60 percent perchloric acid with 500 mL of glacial acetic acid and 30 mL of acetic anhydride, cool, and add glacial acetic acid to make 1000 mL. Allow the prepared solution to stand for 1 day for the excess acetic anhydride to be combined, and determine the water content by Method I (see Water Determination 921), except to use a test specimen of about 5 g of the 0.1 N perchloric acid that is expected to contain approximately 1 mg of water and the Reagent (see Reagent under Method Ia in Water Determination 921) diluted such that 1 mL is equivalent to about 1 to 2 mg of water. If the water content exceeds 0.5%, add more acetic anhydride. If the solution contains no titratable water, add sufficient water to obtain a content of between 0.02% and 0.5% of water. Allow the solution to stand for 1 day, and again titrate the water content. The solution so obtained contains between 0.02% and 0.5% of water, indicating freedom from acetic anhydride. Standardize the solution as follows. Accurately weigh about 700 mg of potassium biphthalate, previously crushed lightly and dried at 120 for 2 hours, and dissolve it in 50 mL of glacial acetic acid in a 250-mL flask. Add 2 drops of crystal violet TS, and titrate with the perchloric acid solution until the violet color changes to blue-green. Deduct the volume of the perchloric acid consumed by 50 mL of the glacial acetic acid. Each 20.423 mg of potassium biphthalate is equivalent to 1 mL of 0.1 N perchloric acid. |
2樓2013-06-05 14:22:55
climbnail
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3樓2013-06-05 15:22:03
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