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[求助]
lammps計(jì)算室溫下Mo的能量有疑問(wèn) 已有1人參與
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# LAMMPS-Mo units metal boundary p p p atom_style atomic lattice bcc 3.147 region Mo block 0 8 0 8 0 8 create_box 1 Mo create_atoms 1 region Mo group Mo region Mo mass 1 95.94 pair_style morse 6.0 pair_coeff 1 1 0.7702 1.4341 3.0122 neighbor 2.0 bin neigh_modify every 1 delay 0 check yes timestep 0.001 velocity Mo create 299 825577 dist gaussian rot yes thermo 100 thermo_style custom step temp enthalpy etotal pe ke press vol minimize 1e-6 1e-6 100000 100000 fix 1 Mo nve reset_timestep 0 run 20000 unfix 1 variable P equal pe variable T equal temp variable Press equal press variable V equal vol variable E equal etotal variable N equal atoms compute rdf Mo rdf 100 1 1 fix 2 Mo ave/time 100 10 1000 c_rdf[1] c_rdf[2] c_rdf[3] file Mo.rdf mode vector fix 1 Mo nvt 270 300 0.1 drag 0.2 run 50000 ---------------------------------------------------------------------------------------------------------------------------------------------------- ------------------------------------------------------------------------------------------------------------------------------------------------------ 因?yàn)槲艺业搅耸覝匾簿褪?98K下Mo的比熱容數(shù)據(jù),所以想通過(guò)比熱容公式 c=dE/(dT*m)來(lái)計(jì)算。經(jīng)過(guò)各種單位換算得到c=(dE*4.18*10^3)/(dT*95.94*10^-3),我想問(wèn)一下,我上面的腳本需要怎么改才能實(shí)現(xiàn)我的目的?希望各位大神暢所欲言 @老虎大王 @月只藍(lán) |

木蟲(chóng) (小有名氣)



木蟲(chóng) (小有名氣)

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