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[求助]
漢譯英，求潤色，122個(gè)字，謝謝。
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在300°C左右，兩個(gè)樣品都出現(xiàn)了模量峰。樣品KS的模量峰值要略高于樣品LS的模量峰值，而峰溫卻低于樣品LS的峰溫。樣品KS和LS經(jīng)過熱處理后產(chǎn)生了元素?cái)U(kuò)散，樣品KS和LS的擴(kuò)散斜率k分別為k1=60.9和k2=45.7，模量峰值分別為E1= 1.6E11和E2 =2.3E11，則單位擴(kuò)散斜率上的模量峰值可用∆E / k表示。 At about 300 ° C, two samples appeared modulus peaks. Modulus peak value of the sample KS was slightly higher than that of the sample LS, while the peak temperature is lower than the peak temperature of the sample LS. After heat treatment samples KS and LS produced element diffusion, and the diffusion slope k of the sample KS and LS were k1 = 60.9 and k2 = 45.7, respectively corresponding to modulus peak value E1 = 1.6E11 and E2 = 2.3E11. ΔE/k represented the modulus peak on unit diffusion slope. |
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【答案】應(yīng)助回帖
★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★
真強(qiáng)必勝: 金幣+1, good 2014-07-12 11:33:18
wxqtjw: 金幣+10, 翻譯EPI+1 2014-07-14 14:49:54
真強(qiáng)必勝: 金幣+1, good 2014-07-12 11:33:18
wxqtjw: 金幣+10, 翻譯EPI+1 2014-07-14 14:49:54
| At about 300 ° C, the modulus peaks of two samples appeared.Modulus peak value of sample KS was slightly higher than sample LS's.But the peak temperature of sample KS is lower than sample LS's.The elements of sample KS and LS have been diffused after heating treatment and the diffusion slope k of the sample KS and LS were k1 = 60.9 and k2 = 45.7,respectively corresponding to modulus peak value were E1 = 1.6E11 and E2 = 2.3E11. ΔE/k represented the modulus peak on unit diffusion slope. |
2樓2014-07-11 15:30:00
【答案】應(yīng)助回帖
★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★
真強(qiáng)必勝: 金幣+1, 多謝 2014-07-12 11:33:36
wxqtjw: 金幣+20, ★★★★★最佳答案 2014-07-14 14:50:02
真強(qiáng)必勝: 金幣+1, 多謝 2014-07-12 11:33:36
wxqtjw: 金幣+20, ★★★★★最佳答案 2014-07-14 14:50:02
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請(qǐng)參考： At about 300 ° C, modulus peaks have been observed in two samples. The value of modulus peak for sample KS was slightly higher than that for sample LS, whereas the peak temperature of KS is lower than that of the sample LS. After treatment by heating, the element diffusion appeared in KS and LS and the diffusion slope k of KS and LS were k1 = 60.9 and k2 = 45.7 respectively and the corresponding value of modulus peak are E1 = 1.6E11 and E2 = 2.3E11. Therefore ΔE/k represents the modulus peak for unit diffusion slope. |
3樓2014-07-12 02:33:06
love林之海
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- 專業(yè): 生物醫(yī)用高分子材料
【答案】應(yīng)助回帖
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At 300 ° C, two samples appeared modulus peak. Modulus modulus peak peak slightly higher than the sample sample KS LS, and the peak temperature is lower than the peak temperature of sample LS. Samples of KS and LS after heat treatment produced the element diffusion, dispersion slope k samples KS and LS were k1=60.9 and k2=45.7, respectively E1= and 1.6E11 modulus peak of E2 =2.3E11, the unit diffusion modulus peak slope can be used on the delta E / K. [ 發(fā)自小木蟲客戶端 ] |
4樓2014-07-12 21:15:41
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