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tuburfransth

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[求助] 關(guān)于支持向量機(jī)的SMO算法偽代碼中有一些問題請教大家已有1人參與

CODE:
target = desired output vector
point = training point matrix
procedure takeStep(i1,i2)
if (i1 == i2) return 0
alph1 = Lagrange multiplier for i1
y1 = target[i1]
E1 = SVM output on point[i1] – y1 (check in error cache)
s = y1*y2
Compute L, H via equations (13) and (14)
if (L == H)
return 0
k11 = kernel(point[i1],point[i1])
k12 = kernel(point[i1],point[i2])
k22 = kernel(point[i2],point[i2])
eta = k11+k22-2*k12
if (eta > 0)
{
a2 = alph2 + y2*(E1-E2)/eta
if (a2 < L) a2 = L
else if (a2 > H) a2 = H
}
else
{
Lobj = objective function at a2=L
Hobj = objective function at a2=H
if (Lobj < Hobj-eps)
a2 = L
else if (Lobj > Hobj+eps)
a2 = H
else
a2 = alph2
}
if (|a2-alph2| < eps*(a2+alph2+eps))
return 0
a1 = alph1+s*(alph2-a2)
Update threshold to reflect change in Lagrange multipliers
Update weight vector to reflect change in a1 & a2, if SVM is linear
Update error cache using new Lagrange multipliers
Store a1 in the alpha array
Store a2 in the alpha array
return 1
endprocedure
procedure examineExample(i2)
y2 = target[i2]
alph2 = Lagrange multiplier for i2
E2 = SVM output on point[i2] – y2 (check in error cache)
r2 = E2*y2
if ((r2 < -tol && alph2 < C) || (r2 > tol && alph2 > 0))
{
if (number of non-zero & non-C alpha > 1)
{
i1 = result of second choice heuristic (section 2.2)
if takeStep(i1,i2)
return 1
}
loop over all non-zero and non-C alpha, starting at a random point
{
i1 = identity of current alpha
if takeStep(i1,i2)
return 1
}
loop over all possible i1, starting at a random point
{
i1 = loop variable
if (takeStep(i1,i2)
return 1
}
}
return 0
endprocedure
main routine:
numChanged = 0;
examineAll = 1;
while (numChanged > 0 | examineAll)
{
numChanged = 0;
if (examineAll)
loop I over all training examples
numChanged += examineExample(I)
else
loop I over examples where alpha is not 0 & not C
numChanged += examineExample(I)
if (examineAll == 1)
examineAll = 0
else if (numChanged == 0)
examineAll = 1
}
代碼見上方，我想請教代碼中的return 0和return 1執(zhí)行后有什么結(jié)果？還有E1 = SVM output on point[i1] – y1 (check in error cache)這行代碼怎么理解？

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1樓 2015-07-14 22:13:13

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fdujian

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【答案】應(yīng)助回帖

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tuburfransth: 金幣+10, ★★★很有幫助 2015-09-02 19:13:13

return 1和0是在main函數(shù)里判斷是否有 alpha 1 和alpha 2 的更新，如果兩個(gè)數(shù)值都更新了，則返回1，若沒更新則為0；

贊一下

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2樓2015-09-02 13:07:10

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