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【求助成功】abinit 計算2X2X2supercell MgO 的DOS (16個原子)
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![]() 如圖我用abinit計算了MgO的DOS圖,其中MgO是2X2X2的超晶包(8個Mg8個O原子),但是,次價帶和價帶怎么就展寬了????求高人解釋 下圖是2個原子的MgO的DOS,,請看兩組圖的差距 ![]() [ Last edited by fanny0007 on 2010-12-8 at 11:05 ] |
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你用的是MgO原胞然后擴成2x2x2的超單胞。 從分?jǐn)?shù)坐標(biāo)可以看出來,超單胞你是借助MS構(gòu)造的,分?jǐn)?shù)坐標(biāo)是正確的。 基矢你不妨也用MS導(dǎo)出來的。注意基矢的長度。 用了rprim后就不用那個angdeg了。我記得以前兩個參數(shù)in文件中同時出現(xiàn)的話會有提示。 僅供參考。 |
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這是我的輸入文件: ndtset 2 #dataset 1 kptopt 1 nshiftk1 4 shiftk1 0.5 0.5 0.5 0.5 0.0 0.0 0.0 0.5 0.0 0.0 0.0 0.5 ngkpt1 8 8 8 prtden1 1 toldfe1 1.0d-6 iscf1 7 #dataset2 DOS iscf2 -3 getden2 1 getwfk2 1 prtdos2 2 #2 OS 3 DOSdosdeltae 0.00005 natsph2 16 ratsph2 1.448 1.448 1.448 1.448 1.448 1.448 1.448 1.448 2.592 2.592 2.592 2.592 2.592 2.592 2.592 2.592 ngkpt2 16 16 16 tolwfr2 1.0d-16 #Definition of the unit cell chkprim 0 diemac 3 acell 3*5.955536 Angstrom angdeg 60 60 60 rprim 0.0 0.5 0.5 0.5 0.0 0.5 0.5 0.5 0.0 ntypat 2 znucl 12 8 natom 16 typat 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 xred 0.2499999999999991 0.2499999999999999 0.2500000000000006 0.7499999999999991 0.2499999999999999 0.2500000000000006 0.2499999999999991 0.7499999999999997 0.2500000000000006 0.7499999999999988 0.7499999999999999 0.2500000000000007 0.2499999999999992 0.2499999999999999 0.7500000000000006 0.7499999999999990 0.2500000000000001 0.7500000000000004 0.2499999999999990 0.7500000000000000 0.7500000000000004 0.7499999999999988 0.7499999999999999 0.7500000000000007 0.0000000000000000 0.0000000000000000 0.0000000000000000 0.4999999999999999 0.0000000000000000 0.0000000000000000 0.0000000000000000 0.4999999999999999 0.0000000000000000 0.4999999999999999 0.4999999999999999 0.0000000000000001 0.0000000000000000 0.0000000000000001 0.4999999999999999 0.4999999999999999 0.0000000000000001 0.4999999999999998 -0.0000000000000001 0.5000000000000001 0.4999999999999999 0.4999999999999998 0.5000000000000000 0.5000000000000001 ecut 24.0 nstep 45 |
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