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fanny0007金蟲(chóng) (小有名氣)
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[交流]
【求助成功】abinit 計(jì)算2X2X2supercell MgO 的DOS (16個(gè)原子)
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![]() 如圖我用abinit計(jì)算了MgO的DOS圖,其中MgO是2X2X2的超晶包(8個(gè)Mg8個(gè)O原子),但是,次價(jià)帶和價(jià)帶怎么就展寬了????求高人解釋 下圖是2個(gè)原子的MgO的DOS,,請(qǐng)看兩組圖的差距 ![]() [ Last edited by fanny0007 on 2010-12-8 at 11:05 ] |
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金蟲(chóng) (小有名氣)
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這是我的輸入文件: ndtset 2 #dataset 1 kptopt 1 nshiftk1 4 shiftk1 0.5 0.5 0.5 0.5 0.0 0.0 0.0 0.5 0.0 0.0 0.0 0.5 ngkpt1 8 8 8 prtden1 1 toldfe1 1.0d-6 iscf1 7 #dataset2 DOS iscf2 -3 getden2 1 getwfk2 1 prtdos2 2 #2 OS 3 DOSdosdeltae 0.00005 natsph2 16 ratsph2 1.448 1.448 1.448 1.448 1.448 1.448 1.448 1.448 2.592 2.592 2.592 2.592 2.592 2.592 2.592 2.592 ngkpt2 16 16 16 tolwfr2 1.0d-16 #Definition of the unit cell chkprim 0 diemac 3 acell 3*5.955536 Angstrom angdeg 60 60 60 rprim 0.0 0.5 0.5 0.5 0.0 0.5 0.5 0.5 0.0 ntypat 2 znucl 12 8 natom 16 typat 2 2 2 2 2 2 2 2 1 1 1 1 1 1 1 1 xred 0.2499999999999991 0.2499999999999999 0.2500000000000006 0.7499999999999991 0.2499999999999999 0.2500000000000006 0.2499999999999991 0.7499999999999997 0.2500000000000006 0.7499999999999988 0.7499999999999999 0.2500000000000007 0.2499999999999992 0.2499999999999999 0.7500000000000006 0.7499999999999990 0.2500000000000001 0.7500000000000004 0.2499999999999990 0.7500000000000000 0.7500000000000004 0.7499999999999988 0.7499999999999999 0.7500000000000007 0.0000000000000000 0.0000000000000000 0.0000000000000000 0.4999999999999999 0.0000000000000000 0.0000000000000000 0.0000000000000000 0.4999999999999999 0.0000000000000000 0.4999999999999999 0.4999999999999999 0.0000000000000001 0.0000000000000000 0.0000000000000001 0.4999999999999999 0.4999999999999999 0.0000000000000001 0.4999999999999998 -0.0000000000000001 0.5000000000000001 0.4999999999999999 0.4999999999999998 0.5000000000000000 0.5000000000000001 ecut 24.0 nstep 45 |
金蟲(chóng) (小有名氣)
金蟲(chóng) (小有名氣)
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