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[求助]
關(guān)于oscillator strength
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大家好,小弟現(xiàn)在有個問題求教:怎么判斷l(xiāng)argest oscillator strength,具體表述如下 CIS calculation of water molecule excited states using optimized structure (1)Point out which exited state corresponding to the largest oscillator strength. Is it singlet or triplet state? What information can you get from the largest oscillator strength? 下面是Gaussian的計算結(jié)果,大家?guī)兔纯,我初學(xué)不太懂。 Excitation energies and oscillator strengths: Excited State 1: Triplet-B1 8.3076 eV 149.24 nm f=0.0000 5 -> 6 0.66381 5 -> 11 -0.21516 This state for optimization and/or second-order correction. Copying the excited state density for this state as the 1-particle RhoCI density. Excited State 2: Singlet-B1 9.2286 eV 134.35 nm f=0.0614 5 -> 6 0.67582 5 -> 11 -0.19312 Excited State 3: Triplet-A1 10.4343 eV 118.82 nm f=0.0000 4 -> 6 0.64966 4 -> 11 -0.23511 Excited State 4: Triplet-A2 10.7033 eV 115.84 nm f=0.0000 5 -> 7 0.54228 5 -> 10 0.43644 Excited State 5: Singlet-A2 11.2918 eV 109.80 nm f=0.0000 5 -> 7 0.56943 5 -> 10 0.40617 Excited State 6: Singlet-A1 11.6278 eV 106.63 nm f=0.1416 4 -> 6 0.65758 4 -> 11 -0.14502 5 -> 9 0.18333 Excited State 7: Triplet-A1 11.9339 eV 103.89 nm f=0.0000 4 -> 8 0.12318 5 -> 9 0.67928 5 -> 15 0.10099 Excited State 8: Triplet-B2 12.3170 eV 100.66 nm f=0.0000 3 -> 6 -0.28256 3 -> 11 0.16297 4 -> 7 0.43444 4 -> 10 0.43403 Excited State 9: Triplet-B1 12.7552 eV 97.20 nm f=0.0000 4 -> 9 0.11919 5 -> 8 0.67575 5 -> 11 0.14887 Excited State 10: Singlet-B1 13.1629 eV 94.19 nm f=0.0275 5 -> 8 0.69442 5 -> 11 0.11507 [ Last edited by zqtian501 on 2011-4-23 at 13:29 ] |
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