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[求助]
求助,ansys建鋼管混凝土模型
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求助各位高手!! 我用ansys建鋼管混凝土的模型,兩端加蓋板,不考慮鋼管和混凝土之間的滑移,我用了很多種方法,但是都不收斂,而且在第一子步就不收斂,所以我覺得是模型建的有問題,但是我換了幾種都不行,所以想請各位幫忙看一下,給點(diǎn)提示,不勝感激。。∠旅媸敲盍 FINISH /CLEAR !(1)工作環(huán)境設(shè)置 /FILNAME,CLO,1 !指定文件名 /TITLE,CLO !指定圖形標(biāo)題 /PREP7 !(2)定義單元類型 ET,1,LINK8 !定義鋼筋的單元類型 ET,2,SOLID65 !定義混凝土的單元類型 KEYOPT,2,1,0 KEYOPT,2,3,0 KEYOPT,2,5,1 KEYOPT,2,6,3 KEYOPT,2,7,1 KEYOPT,2,8,0 ET,3,SOLID45 !定義鋼管的單元類型 KEYOPT,3,1,0 KEYOPT,3,2,1 KEYOPT,3,4,0 KEYOPT,3,5,0 KEYOPT,3,6,0 ET,4,SHELL181 KEYOPT,4,1,0 KEYOPT,4,3,0 KEYOPT,4,8,2 KEYOPT,4,9,0 KEYOPT,4,10,0 !(3)定義實(shí)常數(shù) R,1,50.24E6, , !定義鋼筋的截面面積 R,2, , , , , , , R,3, , R,4,0.06,0.06,0.06,0.06,0,0, !(4)定義鋼材的材料模型及參數(shù) MP,EX,1,2.06E11 MP,PRXY,1,0.25 MP,DENS,1,7850 TB,BISO,1,1,2, 1 !雙線性各向同性強(qiáng)化模型 TBDATA,,235E6,2.06E10 !理想彈塑性模型 !(5)定義混凝土材料 MP,EX,2,32500E6 MP,PRXY,2,0.173 MP,DENS,2,2450 TB,MISO,2,2,14,0 !多線性各向同性強(qiáng)化模型 TBTEMP,0 TBPT,,0.0000593,1.9286E6 !應(yīng)力應(yīng)變數(shù)據(jù)表 TBPT,,0.0003,5.5782E6 TBPT,,0.0006,10.5336E6 TBPT,,0.0009,14.8662E6 TBPT,,0.0012,18.576E6 TBPT,,0.0016,22.5536E6 TBPT,,0.002,25.4239E6 TBPT,,0.0033,27.739E6 TBPT,,0.005,22.267E6 TBPT,,0.01,10.7514E6 TBPT,,0.015,7.911E6 TBPT,,0.02,6.658E6 TBPT,,0.025,5.915E6 TBPT,,0.03,5.40255E6 TB,CONC,2,1,9, TBDATA,,0.3,0.9,1.71E6,-1,,,,0.9 !定義混凝土的破壞參數(shù) !(6)建立幾何模型 K,1,0.244,0.775,0.244 K,2,-0.244,0.775,0.244 K,3,0.244,0.775,-0.244 K,4,-0.244 ,0.775,-0.244 K,5,0.244,-0.775,0.244 K,6,-0.244,-0.775,0.244 K,7,0.244,-0.775,-0.244 K,8,-0.244 ,-0.775,-0.244 K,9,0.244,0.8,0.244 K,10,-0.244,0.8,0.244 K,11,0.244,0.8,-0.244 K,12,-0.244 ,0.8,-0.244 K,13,0.244,-0.8,0.244 K,14,-0.244,-0.8,0.244 K,15,0.244,-0.8,-0.244 K,16,-0.244 ,-0.8,-0.244 V,5,7,8,6,1,3,4,2 !建立混凝土的體1 V,1,3,4,2,9,11,12,10 !建立蓋板的體2和3 V,13,15,16,14,5,7,8,6, VGLUE,ALL !粘結(jié)在一起 /VIEW,1,1,1,1 /ANG,1 VSEL,,,,1 !混凝土的體1賦予屬性 VATT,2,2,2,0 VSEL,S,,,2,3,1 !蓋板的體2和3賦予屬性 VATT,1,3,3,0 ASEL,S,,,2,5,1 !混凝土的體四個(gè)面和蓋板的四個(gè)面賦予shell單元及其他的屬性ASEL,A,,,7,10,1 ASEL,A,,,13,16,1 AATT,1,4,4,0 ALLSEL,ALL LSEL,S,LINE,,5,11,2 !混凝土的豎向線劃分為0.05 LESIZE,ALL,0.05 LSEL,A,LINE,,13,19,2 !兩個(gè)蓋板的豎向線劃分為0.025(和其長度相等) LESIZE,ALL,0.025 LSEL,A,LINE,,25,28,1 LESIZE,ALL,0.025 LSEL,INVE !橫向截面的線劃分為0.048(可整除) LESIZE,ALL,0.0488 ASEL,ALL MSHAPE,0,3D MSHKEY,2 !采用映射網(wǎng)格劃分 AMESH,2,5,1 !對具有殼單元屬性的面進(jìn)行劃分 AMESH,7,10,1 AMESH,13,16,1 ALLSEL,ALL VMESH,1,3,1 !劃分三個(gè)體 NUMMRG,NODE NUMMRG,ELEM NUMMRG,KP FINISH /SOL ANTYPE,0 !靜力分析類型 NLGEOM,1 !打開大變形 NROPT,AUTO,, !自動選擇求解方法 EQSLV,PCG,,O, !PCG求解器 ALLSEL,ALL !(9)施加位移約束 NSEL,S,LOC,Y,0.8 D,ALL,,,,,,UX,,UZ,,,, !蓋板頂加x和z向的水平約束 ALLSEL,ALL NSEL,S,LOC,Y,-0.8 D,ALL,,,,,,UX,UY,UZ,,, !蓋板底加x和y和z向的水平約束 ALLSEL,ALL !(10)施加均布荷載(分7個(gè)荷載步) ALLSEL,ALL NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-10000E3 TIME,1 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,1, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-20000E3 TIME,2 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,2, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-30000E3 TIME,3 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,3, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-40000E3 TIME,4 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,4, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-45000E3 TIME,5 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,5, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-48000E3 TIME,6 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,6, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-51212.76E3 TIME,7 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,7, AUTOTS,1 !打開自動時(shí)間步長 CNVTOL,F,5000,0.05,2,, !定義收斂準(zhǔn)則 CNVTOL,U,,0.03,0,, NEQIT,50, !平衡迭代次數(shù) PRED,ON,,ON !打開預(yù)測器 OUTRES,ALL,ALL !輸出所有子步結(jié)果 LSSOLVE,1,7,1 我還試過鋼管也用solid45單元,建出的模型所有鋼管與混凝土及蓋板之間的接觸部分都是共面的,因?yàn)槲也豢紤]鋼管和混凝土之間的滑移,所以我覺得接觸部分是不是應(yīng)該就沒有問題,但是求解還是不收斂的,做了很久了,一直找不到原因,希望各位可以幫幫忙。。 |
銀蟲 (小有名氣)
銀蟲 (小有名氣)
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由于你打開了大位移選項(xiàng), NLGEOM,1 ,你關(guān)上后肯定立即可以算下去,你的幾何非線性必須考慮么? 考慮幾何非線時(shí),你的子步太小,NSUBST,10可能導(dǎo)致不收斂,建議試試增大至NSUBST,100 另NROPT,AUTO,,與EQSLV,PCG,,O, 可能是矛盾的,建議你查查手冊。 還有這兩句話,只在第7步發(fā)生作用 CNVTOL,F,5000,0.05,2,, !定義收斂準(zhǔn)則 CNVTOL,U,,0.03,0,, |
銀蟲 (小有名氣)
銀蟲 (小有名氣)
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