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[求助]
求助,ansys建鋼管混凝土模型
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求助各位高手。。 我用ansys建鋼管混凝土的模型,兩端加蓋板,不考慮鋼管和混凝土之間的滑移,我用了很多種方法,但是都不收斂,而且在第一子步就不收斂,所以我覺得是模型建的有問題,但是我換了幾種都不行,所以想請各位幫忙看一下,給點提示,不勝感激!。∠旅媸敲盍 FINISH /CLEAR !(1)工作環(huán)境設置 /FILNAME,CLO,1 !指定文件名 /TITLE,CLO !指定圖形標題 /PREP7 !(2)定義單元類型 ET,1,LINK8 !定義鋼筋的單元類型 ET,2,SOLID65 !定義混凝土的單元類型 KEYOPT,2,1,0 KEYOPT,2,3,0 KEYOPT,2,5,1 KEYOPT,2,6,3 KEYOPT,2,7,1 KEYOPT,2,8,0 ET,3,SOLID45 !定義鋼管的單元類型 KEYOPT,3,1,0 KEYOPT,3,2,1 KEYOPT,3,4,0 KEYOPT,3,5,0 KEYOPT,3,6,0 ET,4,SHELL181 KEYOPT,4,1,0 KEYOPT,4,3,0 KEYOPT,4,8,2 KEYOPT,4,9,0 KEYOPT,4,10,0 !(3)定義實常數(shù) R,1,50.24E6, , !定義鋼筋的截面面積 R,2, , , , , , , R,3, , R,4,0.06,0.06,0.06,0.06,0,0, !(4)定義鋼材的材料模型及參數(shù) MP,EX,1,2.06E11 MP,PRXY,1,0.25 MP,DENS,1,7850 TB,BISO,1,1,2, 1 !雙線性各向同性強化模型 TBDATA,,235E6,2.06E10 !理想彈塑性模型 !(5)定義混凝土材料 MP,EX,2,32500E6 MP,PRXY,2,0.173 MP,DENS,2,2450 TB,MISO,2,2,14,0 !多線性各向同性強化模型 TBTEMP,0 TBPT,,0.0000593,1.9286E6 !應力應變數(shù)據表 TBPT,,0.0003,5.5782E6 TBPT,,0.0006,10.5336E6 TBPT,,0.0009,14.8662E6 TBPT,,0.0012,18.576E6 TBPT,,0.0016,22.5536E6 TBPT,,0.002,25.4239E6 TBPT,,0.0033,27.739E6 TBPT,,0.005,22.267E6 TBPT,,0.01,10.7514E6 TBPT,,0.015,7.911E6 TBPT,,0.02,6.658E6 TBPT,,0.025,5.915E6 TBPT,,0.03,5.40255E6 TB,CONC,2,1,9, TBDATA,,0.3,0.9,1.71E6,-1,,,,0.9 !定義混凝土的破壞參數(shù) !(6)建立幾何模型 K,1,0.244,0.775,0.244 K,2,-0.244,0.775,0.244 K,3,0.244,0.775,-0.244 K,4,-0.244 ,0.775,-0.244 K,5,0.244,-0.775,0.244 K,6,-0.244,-0.775,0.244 K,7,0.244,-0.775,-0.244 K,8,-0.244 ,-0.775,-0.244 K,9,0.244,0.8,0.244 K,10,-0.244,0.8,0.244 K,11,0.244,0.8,-0.244 K,12,-0.244 ,0.8,-0.244 K,13,0.244,-0.8,0.244 K,14,-0.244,-0.8,0.244 K,15,0.244,-0.8,-0.244 K,16,-0.244 ,-0.8,-0.244 V,5,7,8,6,1,3,4,2 !建立混凝土的體1 V,1,3,4,2,9,11,12,10 !建立蓋板的體2和3 V,13,15,16,14,5,7,8,6, VGLUE,ALL !粘結在一起 /VIEW,1,1,1,1 /ANG,1 VSEL,,,,1 !混凝土的體1賦予屬性 VATT,2,2,2,0 VSEL,S,,,2,3,1 !蓋板的體2和3賦予屬性 VATT,1,3,3,0 ASEL,S,,,2,5,1 !混凝土的體四個面和蓋板的四個面賦予shell單元及其他的屬性ASEL,A,,,7,10,1 ASEL,A,,,13,16,1 AATT,1,4,4,0 ALLSEL,ALL LSEL,S,LINE,,5,11,2 !混凝土的豎向線劃分為0.05 LESIZE,ALL,0.05 LSEL,A,LINE,,13,19,2 !兩個蓋板的豎向線劃分為0.025(和其長度相等) LESIZE,ALL,0.025 LSEL,A,LINE,,25,28,1 LESIZE,ALL,0.025 LSEL,INVE !橫向截面的線劃分為0.048(可整除) LESIZE,ALL,0.0488 ASEL,ALL MSHAPE,0,3D MSHKEY,2 !采用映射網格劃分 AMESH,2,5,1 !對具有殼單元屬性的面進行劃分 AMESH,7,10,1 AMESH,13,16,1 ALLSEL,ALL VMESH,1,3,1 !劃分三個體 NUMMRG,NODE NUMMRG,ELEM NUMMRG,KP FINISH /SOL ANTYPE,0 !靜力分析類型 NLGEOM,1 !打開大變形 NROPT,AUTO,, !自動選擇求解方法 EQSLV,PCG,,O, !PCG求解器 ALLSEL,ALL !(9)施加位移約束 NSEL,S,LOC,Y,0.8 D,ALL,,,,,,UX,,UZ,,,, !蓋板頂加x和z向的水平約束 ALLSEL,ALL NSEL,S,LOC,Y,-0.8 D,ALL,,,,,,UX,UY,UZ,,, !蓋板底加x和y和z向的水平約束 ALLSEL,ALL !(10)施加均布荷載(分7個荷載步) ALLSEL,ALL NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-10000E3 TIME,1 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,1, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-20000E3 TIME,2 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,2, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-30000E3 TIME,3 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,3, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-40000E3 TIME,4 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,4, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-45000E3 TIME,5 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,5, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-48000E3 TIME,6 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,6, NSEL,S,LOC,Y,0.8 SF ,ALL,PRES,-51212.76E3 TIME,7 KBC,0 NSUBST,10 ALLSEL,ALL LSWRITE,7, AUTOTS,1 !打開自動時間步長 CNVTOL,F,5000,0.05,2,, !定義收斂準則 CNVTOL,U,,0.03,0,, NEQIT,50, !平衡迭代次數(shù) PRED,ON,,ON !打開預測器 OUTRES,ALL,ALL !輸出所有子步結果 LSSOLVE,1,7,1 我還試過鋼管也用solid45單元,建出的模型所有鋼管與混凝土及蓋板之間的接觸部分都是共面的,因為我不考慮鋼管和混凝土之間的滑移,所以我覺得接觸部分是不是應該就沒有問題,但是求解還是不收斂的,做了很久了,一直找不到原因,希望各位可以幫幫忙。! |
銀蟲 (小有名氣)
銀蟲 (小有名氣)
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由于你打開了大位移選項, NLGEOM,1 ,你關上后肯定立即可以算下去,你的幾何非線性必須考慮么? 考慮幾何非線時,你的子步太小,NSUBST,10可能導致不收斂,建議試試增大至NSUBST,100 另NROPT,AUTO,,與EQSLV,PCG,,O, 可能是矛盾的,建議你查查手冊。 還有這兩句話,只在第7步發(fā)生作用 CNVTOL,F,5000,0.05,2,, !定義收斂準則 CNVTOL,U,,0.03,0,, |
銀蟲 (小有名氣)
銀蟲 (小有名氣)
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