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usoado木蟲 (小有名氣)
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[求助]
一個(gè)GAUSSIAN簡單問題,但我太鹺求助
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log文件的內(nèi)容 1/38=1/1; 2/12=2,17=6,18=5,40=1/2; 3/6=3,11=1,16=1,25=14,30=1,116=1/1,2,3,11,14; 4//1; 5/5=1/2; 6/7=2,8=2,9=2,10=2,28=1/1; 99/5=1,9=1,10=8/99; Error converting string" 6.5" to an integer. Out-of-memory error in routine RdGeom-1 (IEnd= 6750021 MxCore= 0) Use %mem=7MW to provide the minimum amount of memory required to complete this step. Error termination via Lnk1e in /home/dgh/g09/l101.exe at Tue Nov 15 10:50:04 2011. Job cpu time: 0 days 0 hours 0 minutes 0.1 seconds. File lengths (MBytes): RWF= 5 Int= 0 D2E= 0 Chk= 1 Scr= 1 lz剛學(xué)習(xí)GAUSSIAN軟件,并按照教程裝了LINUX 64的版本G09,然后想運(yùn)行一下test里面的test000,出現(xiàn)了這個(gè)錯(cuò)誤:Segmentation fault。上面的log文件是輸出文件,大家?guī)兔纯矗以?bashrc里面加了 export GAUSS_MEMDEF=800MW 其他的和網(wǎng)上的安裝教程一樣。這里lz電腦4核8線程,8G內(nèi)存。另外硬盤/home下的容量大概只有150G左右吧。大家看看,這該怎么解決? 謝謝。 |

木蟲 (小有名氣)

新蟲 (小有名氣)
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已經(jīng)提示是Out-of-memory error了 而且建議你用 %mem=7MW to provide the minimum amount of memory required to complete this step. 你既然8G內(nèi)存,可以一開始就設(shè)置大點(diǎn),如你可以在輸入文件中加%mem=500MW 其中1MW=8MB,這樣的話一般就沒什么問題了 |
木蟲 (小有名氣)

木蟲 (小有名氣)
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%mem=500MW ------------------------------------------------------ # SP, RHF/STO-3G punch=archive trakio scf=conventional ------------------------------------------------------ 1/38=1/1; 2/12=2,17=6,18=5,40=1/2; 3/6=3,11=1,16=1,25=14,30=1,116=1/1,2,3,11,14; 4//1; 5/5=1/2; 6/7=2,8=2,9=2,10=2,28=1/1; 99/5=1,9=1,10=8/99; ----------------------------------------- Gaussian Test Job 00 Water with archiving ----------------------------------------- Symbolic Z-matrix: Charge = 0 Multiplicity = 1 O H 1 0.96 H 1 0.96 2 109.47122 1 tetrahedral angles replaced. 1 tetrahedral angles replaced. Input orientation: --------------------------------------------------------------------- Center Atomic Atomic Coordinates (Angstroms) Number Number Type X Y Z --------------------------------------------------------------------- 1 8 0 0.000000 0.000000 0.000000 2 1 0 0.000000 0.000000 0.960000 3 1 0 0.905097 0.000000 -0.320000 --------------------------------------------------------------------- Distance matrix (angstroms): 1 2 3 1 O 0.000000 2 H 0.960000 0.000000 3 H 0.960000 1.567673 0.000000 Stoichiometry H2O Framework group C2V[C2(O),SGV(H2)] Deg. of freedom 2 Full point group C2V NOp 4 Largest Abelian subgroup C2V NOp 4 Largest concise Abelian subgroup C2 NOp 2 Standard orientation: --------------------------------------------------------------------- Center Atomic Atomic Coordinates (Angstroms) Number Number Type X Y Z --------------------------------------------------------------------- 1 8 0 0.000000 0.000000 0.110851 2 1 0 0.000000 0.783837 -0.443405 3 1 0 0.000000 -0.783837 -0.443405 --------------------------------------------------------------------- Rotational constants (GHZ): 919.0227225 408.0852053 282.5991530 Standard basis: STO-3G (5D, 7F) There are 4 symmetry adapted basis functions of A1 symmetry. There are 0 symmetry adapted basis functions of A2 symmetry. There are 1 symmetry adapted basis functions of B1 symmetry. There are 2 symmetry adapted basis functions of B2 symmetry. Integral buffers will be 131072 words long. Raffenetti 1 integral format. Two-electron integral symmetry is turned on. 7 basis functions, 21 primitive gaussians, 7 cartesian basis functions 5 alpha electrons 5 beta electrons nuclear repulsion energy 9.1571759100 Hartrees. NAtoms= 3 NActive= 3 NUniq= 2 SFac= 1.69D+00 NAtFMM= 80 NAOKFM=F Big=F One-electron integrals computed using PRISM. NBasis= 7 RedAO= T NBF= 4 0 1 2 NBsUse= 7 1.00D-06 NBFU= 4 0 1 2 對(duì)了log變成這樣了。 |

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