雖然你要求用mathematica8解這個(gè)方程的整數(shù)解。但是我不會(huì)mathematica8這個(gè)軟件。我用Fortran編寫了一段小程序，給你解了一下。為了減小計(jì)算量，首先解了一下非負(fù)整數(shù)解如下：
x = 10  y =    2  z = 80
x = 10  y =    7  z = 77
x = 10  y = 12  z = 74
x = 10  y = 17  z = 71
x = 10  y = 22  z = 68
x = 10  y = 27  z = 65
x = 10  y = 32  z = 62
x = 10  y = 37  z = 59
x = 10  y = 42  z = 56
x = 10  y = 47  z = 53
x = 10  y = 52  z = 50
x = 10  y = 57  z = 47
x = 10  y = 62  z = 44
x = 10  y = 67  z = 41
x = 10  y = 72  z = 38
x = 10  y = 77  z = 35
x = 10  y = 82  z = 32
x = 10  y = 87  z = 29
x = 10  y = 92  z = 26
x = 10  y = 97  z = 23
x = 10  y = 102  z = 20
x = 10  y = 107  z = 17
x = 10  y = 112  z = 14
x = 10  y = 117  z = 11
x = 10  y = 122  z =    8
x = 10  y = 127  z =    5
x = 10  y = 132  z =    2
x = 25  y =    0  z = 63
x = 25  y =    5  z = 60
x = 25  y = 10  z = 57
x = 25  y = 15  z = 54
x = 25  y = 20  z = 51
x = 25  y = 25  z = 48
x = 25  y = 30  z = 45
x = 25  y = 35  z = 42
x = 25  y = 40  z = 39
x = 25  y = 45  z = 36
x = 25  y = 50  z = 33
x = 25  y = 55  z = 30
x = 25  y = 60  z = 27
x = 25  y = 65  z = 24
x = 25  y = 70  z = 21
x = 25  y = 75  z = 18
x = 25  y = 80  z = 15
x = 25  y = 85  z = 12
x = 25  y = 90  z =    9
x = 25  y = 95  z =    6
x = 25  y = 100  z =    3
x = 25  y = 105  z =    0
x = 40  y =    3  z = 43
x = 40  y =    8  z = 40
x = 40  y = 13  z = 37
x = 40  y = 18  z = 34
x = 40  y = 23  z = 31
x = 40  y = 28  z = 28
x = 40  y = 33  z = 25
x = 40  y = 38  z = 22
x = 40  y = 43  z = 19
x = 40  y = 48  z = 16
x = 40  y = 53  z = 13
x = 40  y = 58  z = 10
x = 40  y = 63  z =    7
x = 40  y = 68  z =    4
x = 40  y = 73  z =    1
x = 55  y =    1  z = 26
x = 55  y =    6  z = 23
x = 55  y = 11  z = 20
x = 55  y = 16  z = 17
x = 55  y = 21  z = 14
x = 55  y = 26  z = 11
x = 55  y = 31  z =    8
x = 55  y = 36  z =    5
x = 55  y = 41  z =    2
x = 70  y =    4  z =    6
x = 70  y =    9  z =    3
x = 70  y = 14  z =    0

在[-1000,1000]這個(gè)區(qū)間內(nèi)的整數(shù)就有33177組。估計(jì)你的這個(gè)問題也是有實(shí)際應(yīng)用的，所以我覺得你肯定是有區(qū)間界定的。因此我把我的代碼放在這兒，你可以通過調(diào)整這個(gè)區(qū)間的上下線來尋找你想要的結(jié)果：

   program sovl
      integer*4 i, j, k
      integer*4 max_x, max_y, max_z
      real*8 resu,EPS
parameter (EPS=1.d-300)

max_x=int(70d0/0.91d0)+1
max_y=int(70d0/0.45d0)+1
      max_z=int(70d0/0.75d0)+1
      open(unit=100,file="solv.dat"

do i=-1000,1000,1
   do j=-1000,1000,1
                  do k=-1000,1000,1
      resu=(real(i)*0.91d0+real(j)*0.45d0+real(k)*0.75d0)
      if(abs(resu-70d0)    write(*,'(a4,I5,2x,a4,I5,2x,a4,I5)')"x = ",i,"y = ",j,"z = ",k
   write(100,'(a4,I5,2x,a4,I5,2x,a4,I5)')"x = ",i,"y = ",j,"z = ",k
   endif

      enddo
            enddo
         enddo

      end program sovl

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附件 1 : solv2.f

2012-06-04 21:48:57, 631 bytes

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4樓2012-06-04 21:50:20

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【答案】應(yīng)助回帖

★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★ ★
shangxj: 金幣+10, ★★★很有幫助, 寫程序解決問題對(duì)我來說有點(diǎn)難度，我還是想使用簡單的工具解決相關(guān)的一類問題。只是平時(shí)雜事頗多，靜不下心來深入去學(xué)。 2012-06-06 17:53:38
csgt0: 金幣+2, 多謝應(yīng)助 2012-09-19 09:46:09

考慮到你可能不能編譯fortran程序，我將fortran程序做成可執(zhí)行文件了。你只需要下載那個(gè)exe按照提示輸入你的求解范圍，就可以直接將結(jié)果輸出到文件中去了。

希望對(duì)你有用。

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本內(nèi)容由用戶自主發(fā)布，如果其內(nèi)容涉及到知識(shí)產(chǎn)權(quán)問題，其責(zé)任在于用戶本人，如對(duì)版權(quán)有異議，請(qǐng)聯(lián)系郵箱：xiaomuchong@tal.com
附件 1 : solv2.f

2012-06-04 22:10:38, 1.6 K

附件 2 : solv2.exe

2012-06-04 22:10:43, 344.03 K

弘德明志博學(xué)篤行

5樓2012-06-04 22:10:50

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