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wangxinling新蟲 (小有名氣)
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[求助]
方程解的個數(shù),求高手幫忙。急。
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a1,b1,c1,d1,e1,a2,b2,c2,d2,e2,a3,b3,c3,d3,e3,是未知數(shù),下面的是方程組。這個方程組解是多少?唯一嗎? e1=1 a1+b1+c1+d1+e1=0 a2+b2+c2+d2+e2=0 16a2+8b2+4c2+2d2+e2=0 16a3+8b3+4c3+2d3+e3=0 81a3+27b3+9c3+3d3+e3=0 d1=0 4a1+3b1+2c1+d1=4a2+3b2+2c2+d2=0 32a2+12b2+4c2+d2=32a3+12b3+4c3+d3 108a3+27b3+6c3+d3=0 12a1+6b1+2c1=12a2+6b2+2c2 48a2+12b2+2c2=48a3+12b3+2c3 108a3+18b3+2c3=0 a1+a2+a3=0 52a3+5b3+20a2+3b2+4a1+b1=0 136a2+54b2+20c2+6d2=-1 |

新蟲 (小有名氣)

版主 (著名寫手)
版主 (著名寫手)
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如果第九行沒有輸入錯誤,就有兩組解 第一組(Sqrt是平方根) a1 = 1/52 (-36 + Sqrt[789]), b1 = 1/26 (88 - Sqrt[789]), c1= 1/52 (-192 + Sqrt[789]), d1 =0, e1 = 1, a2= 1/52 (23 - Sqrt[789]), b2= 1/52 (-151 + 6 Sqrt[789]), c2= 1/4 (27 - Sqrt[789]), d2 =1/52 (-341 + 12 Sqrt[789]), e2 = 1/26 (59 - 2 Sqrt[789]), a3 =1/4, b3 = -(11/ 4), c3= 45/4, d3= -(81/4), e3 = 27/2 第二組 a1= 1/52 (-36 - Sqrt[789]), b1 = 1/26 (88 + Sqrt[789]), c1 = 1/52 (-192 - Sqrt[789]), d1 =0, e1 = 1, a2 = 1/52 (23 + Sqrt[789]), b2= 1/52 (-151 - 6 Sqrt[789]), c2 = 1/4 (27 + Sqrt[789]), d2 =1/52 (-341 - 12 Sqrt[789]), e2 = 1/26 (59 + 2 Sqrt[789]), a3 = 1/4, b3 = -(11/ 4), c3 = 45/4, d3= -(81/4), e3 = 27/2 |
新蟲 (小有名氣)

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