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fanqy1991金蟲 (著名寫手)
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[求助]
幾何優(yōu)化有三個(gè)能量值 我該看哪一個(gè)?
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Final energy, E = -12266.31912109 eV Final free energy (E-TS) = -12266.33460092 eV (energies not corrected for finite basis set) NB est. 0K energy (E-0.5TS) = -12266.32686101 eV 如上述,真有這么三個(gè)能量值,我該看哪一個(gè)能量值來確定它是不是收斂?求大神賜教 |
計(jì)算 |

金蟲 (著名寫手)
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是的,都收斂, +-----------+-----------------+-----------------+------------+-----+ <-- BFGS | Parameter | value | tolerance | units | OK? | <-- BFGS +-----------+-----------------+-----------------+------------+-----+ <-- BFGS | dE/ion | 7.491404E-008 | 5.000000E-006 | eV | Yes | <-- BFGS | |F|max | 8.616090E-003 | 1.000000E-002 | eV/A | Yes | <-- BFGS | |dR|max | 6.978532E-005 | 5.000000E-004 | A | Yes | <-- BFGS | Smax | 6.914192E-003 | 2.000000E-002 | GPa | Yes | <-- BFGS +-----------+-----------------+-----------------+------------+-----+ <-- BFGS 但是我不知道該看哪一個(gè)能量值,您能幫我明確指出來嗎? |
金蟲 (著名寫手)

金蟲 (著名寫手)
銀蟲 (小有名氣)
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lz是用castep計(jì)算的吧,收斂了,是有三個(gè)能量值。具體參見help文件,我復(fù)制粘貼一部分: The CASTEP output is as follows. The line Final energy, E = -861.8315373731 eV gives the Kohn-Sham energy, EKS, which ignores the entropy. However, it is the total Mermin free energy that is minimized by CASTEP and reported in the SCF cycles in the line Final free energy (E-TS) = -861.8315374521 eV If you were actually interested in the electronic states at some reasonable nonzero temperature, you would smear the Fermi level with a thermal (i.e., Fermi-Dirac) smearing method and the free energy reported by CASTEP would be the value you require. However, it is often the T = 0 K value that is required and the smearing is necessary to improve the convergence of the numerical algorithm. Because the dependence of the free energy and the Kohn-Sham energy on the smearing width is the same (to first order), averaging the two values gives a much better approximation to the T = 0 K result: NB est. 0K energy (E-0.5TS) = -861.8315374126 eV |

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