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cooooldog鐵桿木蟲(chóng) (著名寫(xiě)手)
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一個(gè)看起來(lái)簡(jiǎn)單的不太容易的定積分問(wèn)題 已有9人參與
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求如下定積分的解析形式,希望解析形式中不出現(xiàn)變量,即結(jié)果只是常量的函數(shù)形式。 比如,橢圓積分表達(dá)不符合要求。 此外:可積性是顯然的: [ Last edited by cooooldog on 2017-7-15 at 18:34 ] |

鐵桿木蟲(chóng) (職業(yè)作家)
科苑小木蟲(chóng)
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iint('x*sin(x)*(x^5+1)^(-1/2)',0,1) ans = 10^(1/2)*pi*(-1)^(1/5)*(2^(1/10)*sec(3/10*pi)*csc(2/5*pi)*sin(1/10*pi)^2*gamma(4/5)/pi*gamma(9/10)/gamma(7/10)*hypergeom([],[1/5, 2/5, 1/2, 11/20, 3/5, 7/10, 9/10, 21/20, 11/10],-1/10000000000)-1/30*2^(1/2)/pi*hypergeom([1],[2/5, 3/5, 7/10, 3/4, 4/5, 9/10, 11/10, 6/5, 5/4, 13/10],-1/10000000000)*tan(3/10*pi)*csc(2/5*pi)*sin(1/10*pi)+1/5400*2^(9/10)*hypergeom([],[3/5, 4/5, 9/10, 19/20, 11/10, 13/10, 7/5, 29/20, 3/2],-1/10000000000)*tan(1/10*pi)*csc(1/5*pi)^2*sin(3/10*pi)*gamma(7/10)/gamma(4/5)/gamma(9/10)-1/24570*2^(3/10)/pi*hypergeom([],[4/5, 11/10, 23/20, 6/5, 13/10, 3/2, 8/5, 33/20, 17/10],-1/10000000000)*tan(3/10*pi)*csc(2/5*pi)^2*cos(1/5*pi)*sin(1/10*pi)*gamma(7/10)*gamma(9/10)/gamma(3/5)+1/35985600*2^(7/10)*hypergeom([],[6/5, 13/10, 27/20, 7/5, 3/2, 17/10, 9/5, 37/20, 19/10],-1/10000000000)*sec(1/10*pi)*cot(1/5*pi)*gamma(3/5)/gamma(7/10)/gamma(9/10)+2*i*pi*(2^(1/10)/pi^2*csc(2/5*pi)*sin(1/10*pi)^2*gamma(4/5)*gamma(9/10)/gamma(7/10)*(-1)^(1/5)*hypergeom([],[1/5, 2/5, 1/2, 11/20, 3/5, 7/10, 9/10, 21/20, 11/10],-1/10000000000)-1/30*2^(1/2)*(-1)^(2/5)/pi^2*hypergeom([1],[2/5, 3/5, 7/10, 3/4, 4/5, 9/10, 11/10, 6/5, 5/4, 13/10],-1/10000000000)*tan(3/10*pi)*sin(1/10*pi)+1/5400*2^(9/10)/pi*csc(1/5*pi)^2*sin(1/10*pi)/gamma(4/5)/gamma(9/10)*sin(3/10*pi)*gamma(7/10)*(-1)^(3/5)*hypergeom([],[3/5, 4/5, 9/10, 19/20, 11/10, 13/10, 7/5, 29/20, 3/2],-1/10000000000)-1/24570*2^(3/10)/pi^2*csc(2/5*pi)^2*cos(1/5*pi)/gamma(3/5)*sin(3/10*pi)*gamma(7/10)*sin(1/10*pi)*gamma(9/10)*(-1)^(4/5)*hypergeom([],[4/5, 11/10, 23/20, 6/5, 13/10, 3/2, 8/5, 33/20, 17/10],-1/10000000000))) 上面那個(gè)錯(cuò)了,這里更正了,()^(-1/2)。。。。。依然很長(zhǎng),哈哈哈哈哈 |

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