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[求助]
從LAMMPS得到的原子速度,如何計(jì)算速度自相關(guān)函數(shù)(VAF)?求助 已有3人參與
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| 比如說我的系統(tǒng)里有4000個(gè)原子,在某個(gè)狀態(tài)下跑了100步,每一步的時(shí)間間隔是確定的(2fs),每一步時(shí)每個(gè)原子的三維速度都會(huì)輸出。我想計(jì)算這個(gè)系統(tǒng)的速度自相關(guān)函數(shù)VAF,計(jì)算公式是<v(0)·v(t)> 。我不太明白這個(gè)公式的含義是計(jì)算什么,用FORTRAN或MATLAB應(yīng)該如何編程實(shí)現(xiàn)呢?緊急求助,不勝感激。 |
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% a matlab script for calculating VACF from velocity data clear; load v.txt; % assume your velocity data are in the above file and assume the format is (N is the number of atoms, M is the number of time points): % vx_1 vy_1 vz_1 % time point 1 % vx_2 vy_2 vz_2 % time point 1 % ... % time point 1 % vx_N, vy_N, vz_N % time point 1 % vx_1 vy_1 vz_1 % time point 2 % vx_2 vy_2 vz_2 % time point 2 % ... % time point 2 % vx_N, vy_N, vz_N % time point 2 % ... % vx_1 vy_1 vz_1 % time point M % vx_2 vy_2 vz_2 % time point M % ... % time point M % vx_N, vy_N, vz_N % time point M N = xxx; % number of atoms in your system M = length(v)/N; % number of time points for your velocity data dt = xxx; % the time interval between two set of velocities (in some unit) Nt = xxx; % maximum length of the correlation your want (usually Nt = M/10 is a good choice) time = dt*(0:Nt-1); M = M-Nt; % you have to waste a small portion of data vacf=zeros(Nt,1); for nt=0:Nt-1 for m=1:M vacf(nt+1, =sum(sum(v_all((m-1)*N+1:m*N, .*v_all((m+nt-1)*N+1 m+nt)*N, ));end end %vacf=vacf/M; % you can also normalize it by using [vacf=vacf(1);] if you want % now you can plot the result: close all; figure; plot(time, vacf,'o-'); xlabel('time (some unit)'); ylabel('VACF (some unit)'); |
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