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【求助】請(qǐng)教molpro計(jì)算中出現(xiàn)的一個(gè)問(wèn)題
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如題,我在對(duì)Na2分子的x1sigma+g, a3pi, A1sgma+u,B1PIU, C1PIU, D1PIU, E1PIU進(jìn)行掃描的時(shí)候,我的輸入卡如下: memory,30,m geometry={na1;na2,na1,r1(i)} distance= [2.1,2.3,2.5,2.6,2.8,2.9,2.95,3.0,3.05,3.1,3.15,3.2,3.42,3.62,3.9,4.2,4.5,4.8,5.3,5.7,5.8,5.9,6.0,6.2,6.4,6.6,6.8,7.0,7.2,7.4,7.6,7.8,8.0,8.2,8.4,8.6,8.8,9.0] ang basis=VTZ r1(1)=distance(1) hf,occ,4,1,1,0,3,1,1,0;core,3,1,1,0,3,1,1,0; i=0 do ir1=1,#distance i=i+1 r1(i)=distance(ir1) multi; occ,4,1,1,0,3,1,1,0;core,3,1,1,0,3,1,1,0;wf,22,1,0;state,2,refstate,1,2;wf,22,5,0;state,1;wf,22,2,0,state,4,refstate,1,2,3,4;lquant,1; ecas(i)=energy(1) ci;occ,4,1,1,0,3,1,1,0;core,3,1,1,0,3,1,1,0;wf,22,1,0;state,2;wf,22,5,0;state,1;wf,22,2,0,state,4 emrci(i)=energy(1) emrciq(i)=energd(1) enddo 但是計(jì)算的結(jié)果始終出現(xiàn)如下信息: State symmetry 3 State symmetry 3: Projection for operator LZ squared value = 1 Number of electrons: 2 Spin symmetry=Singlet Space symmetry=2 Number of states: 1 Number of CSFs: 0 ( 0 determinants, 1 intermediate states) Valence orbitals read from record 2100.2 Type=RHF/CANONICAL (state 1.1) Frozen core orbitals read from record 2100.2 Type=RHF/CANONICAL (state 1.1) EXTRA SYMMETRY OF MOS IN SYMMETRY 1: 0 0 0 1 1 1 1 2 1 1 2 2 1 1 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 2: 0 1 1 1 1 1 2 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 3: 0 1 1 1 1 1 2 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 5: 0 0 0 1 1 1 1 2 1 1 2 1 2 1 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 6: 0 1 1 1 1 2 1 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 7: 0 1 1 1 1 2 1 1 Wavefunction dump at record 2140.2 Convergence thresholds 0.10E-01 (gradient) 0.10E-05 (energy) 0.10E-02 (step length) Weight factors for state symmetry 1: 0.25000 0.25000 Weight factors for state symmetry 2: 0.25000 Weight factors for state symmetry 3: 0.25000 Number of orbital rotations 11 ( 0 Core/Active 0 Core/Virtual 0 Active/Active 11 Active/Virtual) Total number of variables = 13 ITER. MIC NCI NEG ENERGY(VAR) ENERGY(PROJ) ENERGY CHANGE GRAD(0) GRAD(ORB) GRAD(CI) STEP TIME MORE STATES THAN CONFIGURATIONS SPECIFIED: 1 2 懇請(qǐng)高手幫我修改下輸入卡,看怎么樣才能消除這個(gè)錯(cuò)誤,萬(wàn)分感謝。 |
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專家經(jīng)驗(yàn): +458 |
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老哥,你好我的全部輸入卡修改為 **,Na2 memory,30,m geometry={na1;na2,na1,r1(i)} distance= [2.1,2.3,2.5,2.6,2.8,2.9,2.95,3.0,3.05,3.1,3.15,3.2,3.42,3.62,3.9,4.2,4.5,4.8,5.3,5.7,5.8,5.9,6.0,6.2,6.4,6.6,6.8,7.0,7.2,7.4,7.6,7.8,8.0,8.2,8.4,8.6,8.8,9.0] ang basis=VTZ r1(1)=distance(1) hf,occ,4,1,1,0,3,1,1,0;core,3,1,1,0,3,1,1,0; i=0 do ir1=1,#distance i=i+1 r1(i)=distance(ir1) multi; occ,4,1,1,0,3,1,1,0;core,3,1,1,0,3,1,1,0;wf,22,1,0;state,2;wf,22,5,0;state,1;wf,22,2,0,state,4;lquant,1,1,1,1; ecas(i)=energy(1) ci;occ,4,1,1,0,3,1,1,0;core,3,1,1,0,3,1,1,0;wf,22,1,0;state,2;wf,22,5,0;state,1;wf,22,2,0,state,4 emrci(i)=energy(1) emrciq(i)=energd(1) enddo table,r1,ecas,emrci,emrciq head,r1,ecas,emrci,emrciq save,na2.tab 輸出信息 還是 State symmetry 3 State symmetry 3: Projection for operator LZ squared value = 1 Number of electrons: 2 Spin symmetry=Singlet Space symmetry=2 Number of states: 1 Number of CSFs: 0 ( 0 determinants, 1 intermediate states) Valence orbitals read from record 2100.2 Type=RHF/CANONICAL (state 1.1) Frozen core orbitals read from record 2100.2 Type=RHF/CANONICAL (state 1.1) EXTRA SYMMETRY OF MOS IN SYMMETRY 1: 0 0 0 1 1 1 1 2 1 1 2 2 1 1 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 2: 0 1 1 1 1 1 2 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 3: 0 1 1 1 1 1 2 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 5: 0 0 0 1 1 1 1 2 1 1 2 1 2 1 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 6: 0 1 1 1 1 2 1 1 EXTRA SYMMETRY OF MOS IN SYMMETRY 7: 0 1 1 1 1 2 1 1 Wavefunction dump at record 2140.2 Convergence thresholds 0.10E-01 (gradient) 0.10E-05 (energy) 0.10E-02 (step length) Weight factors for state symmetry 1: 0.25000 0.25000 Weight factors for state symmetry 2: 0.25000 Weight factors for state symmetry 3: 0.25000 Number of orbital rotations 11 ( 0 Core/Active 0 Core/Virtual 0 Active/Active 11 Active/Virtual) Total number of variables = 13 ITER. MIC NCI NEG ENERGY(VAR) ENERGY(PROJ) ENERGY CHANGE GRAD(0) GRAD(ORB) GRAD(CI) STEP TIME MORE STATES THAN CONFIGURATIONS SPECIFIED: 1 2 懇請(qǐng)老哥幫忙。謝謝 |
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從這一段來(lái)看 Weight factors for state symmetry 1: 0.25000 0.25000 Weight factors for state symmetry 2: 0.25000 Weight factors for state symmetry 3: 0.25000 symmetry 3 只算了一個(gè)態(tài),與你之前設(shè)定的 wf,22,2,0,state,4; 不符 不如刪去 lquant,1,1,1,1; 試試... |
專家顧問(wèn) (職業(yè)作家)
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