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[求助]
matlab擬合擬均相動(dòng)力學(xué)參數(shù)
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模型如附件所示,要求里面的k+,k-,m,n,p,我自己編了個(gè)程序,但是一直有問題 M文件 function f=fortyfour_D(c,t,rD) t=[5,10,15,20,30,45,60,80,100,120,150,180,210,240,300,360]; CD=[749.16 ,994.49 ,1382.00,1589.18,1909.81,2222.86,2525.68,2721.90,2896.67,2951.42,2960.67,2999.60,3017.97,3048.91,3072.27,3063.85]; knots = 3;K = 3; %三次B樣條 sp=spap2(knots,K,t,CD); sp=spap2(newknt(sp),K,t,CD); pp=fnder(sp); % 計(jì)算B樣條函數(shù)的導(dǎo)函數(shù) dCDdt=fnval(pp,t); % 計(jì)算t處的導(dǎo)函數(shù)值 Wcat=85.6312 %催化劑濃度 rD=dCDdt./Wcat; f=c(1)*CA.^c(2)*CB.^c(3)-c(4)*CD.^c(5)))-rD; 命令如下 c0=[1,1,1,1,1]; for i=1:100 c=lsqnonlin('fortyfour_D ',c0); c0=c; end c % 繪制圖形 ti = linspace(t(1),t(end),200); %y=linspace(a,b,n)生成一個(gè)行向量,該向量將a與b之間平分為n個(gè)點(diǎn),包含端點(diǎn)a和b。 CDi = fnval(sp,ti); %計(jì)算樣條函數(shù)區(qū)間內(nèi)任意一點(diǎn)的值 plot(t,CD,'ro',ti,CDi,'b-'),xlabel('t'),ylabel('C_D') legend('實(shí)驗(yàn)數(shù)據(jù)','擬合曲線') c=[1,1,1,1,1];for i=1:100;c=lsqnonlin('fortyfour_D ',c);c;end CD=[749.16 ,994.49 ,1382.00,1589.18,1909.81,2222.86,2525.68,2721.90,2896.67,2951.42,2960.67,2999.60,3017.97,3048.91,3072.27,3063.85]; CA = [2732.43 2468.85 2223.97 2023.64 1696.41 1343.42 1054.34 902.20 756.91 717.86 703.53 631.00 652.41 649.53 624.92 744.95]; CB= [3127.04 2722.48 2414.51 2267.55 1927.70 1500.17 1285.07 1111.91 924.27 886.32 830.86 821.82 801.97 780.39 794.41 783.73]; rD=[0.5631,0.5282,0.4934,0.4585,0.3888,0.2842,0.1796,0.0482,0.0404,0.0326,0.0209,0.0092,0.0046,0.0040,0.0028,0.0015]; >> c0=[1,1,1,1,1]; for i=1:1000 c=lsqcurvefit('ffD ',c0,CD,rD); c0=c; end c 請大家?guī)兔纯次页绦蚰睦镉袉栴}[ Last edited by lxyy on 2011-12-30 at 16:05 ] |
鐵桿木蟲 (職業(yè)作家)
鐵桿木蟲 (職業(yè)作家)
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M文件 function f=q(c,t,CD,rD) t=[0 0.08333 0.166667 0.25 0.5 0.75 1 1.5 2 2.666667 3.333333 4 5]; CD=[0 0.53259 1.154323 1.621033 2.644088 3.163488 3.461446 3.710468 3.784974 3.746928 3.761759 3.713404 3.643825]; rD=[0.0710291014584411 0.0700187830917774 0.0655437729479848 0.0576582625377526 0.0329826401194250 0.0166083513736405 0.00912074378901541 0.00278932296049053 0.000202497370868135 0 0 0 0]; f= c(1)*((4.6026-CD).^c(2)*(5.064335-CD).^c(3)-c(4)*CD.^c(5))-rD; 命令如下 c0=[0.1,0.1,0.1,0.1,0.1]; for i=1:50 c=lsqnonlin('q ',c0); c0=c; end c 我把程序簡化了下,還是一直運(yùn)行不了 |
銅蟲 (正式寫手)
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