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smileheaven

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[求助] MATLAB非線性優(yōu)化擬合怎么改才正確

想對(duì)函數(shù)z求一下x和Fval的最優(yōu)解，其中x1的取值范圍在0.3到1.8，x2的取值范圍在1到2，均為閉區(qū)間。以下是自己編的程序
function [x fval history] = myproblem1(x0)
      history = []
      options = optimset('OutputFcn', @myoutput)
      [x fval] = fminsearch(@objfun, x0,options)
      function stop = myoutput(x,optimvalues,state)
         stop=[]
         if state == 'iter'
            history = [history; x]
         end
      end
      function z = objfun(x)
         z = 124.5993*x(1)^2-371.4544*x(1)+712.1124-1359.4398*x(2)^2+4028.7765*x(2)-2244.7098
      end
end
但是返回的錯(cuò)誤卻是
??? In an assignment  A(

= B, the number of elements in A and B
must be the same.

Error in ==> callAllOptimOutputFcns at 12
stop(i) = feval(OutputFcn{i},xOutputfcn,optimValues,state,varargin{:});

Error in ==> fminsearch>callOutputAndPlotFcns at 478
stop = callAllOptimOutputFcns(outputfcn,xOutputfcn,optimValues,state,varargin{:}) || stop;

Error in ==> fminsearch at 213
[xOutputfcn, optimValues, stop] = callOutputAndPlotFcns(outputfcn,plotfcns,v(:,1),xOutputfcn,'init',itercount, ...

Error in ==> myproblem1 at 4
[x fval history] = fminsearch(@objfun, x0,options)
請(qǐng)各位蟲哥蟲姐幫忙看看，謝謝啦

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探求、奮斗、不達(dá)目的誓不罷休

1樓 2012-05-25 12:26:39

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smileheaven

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引用回帖:

2樓: Originally posted by csgt0 at 2012-05-25 13:35:05
stop=false;

結(jié)果
state =

done

Exiting: Maximum number of function evaluations has been exceeded
- increase MaxFunEvals option.
Current function value: -319813720581 ...

那為什么我這邊計(jì)算不出來呢？什么地方錯(cuò)了，如果可能，還請(qǐng)您指教，謝謝

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探求、奮斗、不達(dá)目的誓不罷休

3樓2012-05-25 14:01:02

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查看全部 4 個(gè)回答

csgt0

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【答案】應(yīng)助回帖

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感謝參與，應(yīng)助指數(shù) +1
smileheaven: 金幣+5, ★★★★★最佳答案, 謝謝 2012-06-11 12:18:10

stop=false;

結(jié)果
state =

done

Exiting: Maximum number of function evaluations has been exceeded
      - increase MaxFunEvals option.
      Current function value: -31981372058113011000000000000000000000000000000000000000000000000000000000000000000000000000.000000

x =

  1.0e+044 *

0.1905 1.5349

fval =

-3.1981e+091

result =

  1.0e+044 *

0.1905 1.5349

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showmethemoney

2樓2012-05-25 13:35:05

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csgt0

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【答案】應(yīng)助回帖

stop只能是false或true，然后通過stop來判斷是否跳出。你不用它就設(shè)為false，而不是[];再用state判斷

Stop Flag

The output argument stop is a flag that is true or false. The flag tells the optimization function whether the optimization should quit or continue. The following examples show typical ways to use the stop flag.
Stopping an Optimization Based on Data in optimValues

The output function can stop an optimization at any iteration based on the current data in optimValues. For example, the following code sets stop to true if the objective function value is less than 5:

function stop = myoutput(x, optimValues, state)
stop = false;
% Check if objective function is less than 5.
if optimValues.fval < 5
stop = true;
end

Stopping an Optimization Based on GUI Input

If you design a GUI to perform optimizations, you can make the output function stop an optimization when a user clicks a Stop button on the GUI. The following code shows how to do this, assuming that the Stop button callback stores the value true in the optimstop field of a handles structure called hObject stored in appdata.

function stop = myoutput(x, optimValues, state)
stop = false;
% Check if user has requested to stop the optimization.
stop = getappdata(hObject,'optimstop');

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showmethemoney

4樓2012-05-25 14:25:43

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